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2 years ago

Motion is a change in an object

Chemistry

2 answers:

lyudmila [28]2 years ago

8 0

Answer:

motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time.

Explanation:

Vanyuwa [196]2 years ago

5 0

Answer:

why is this in chemistry? this is physics.

Explanation:

Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time.

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Aluminum oxide (Al2O3) is a widely used industrial abrasive (known as emery or corundum), for which the specific application dep

ivanzaharov [21]

Answer:

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Based on the chemical formula of the compound, that is, Al2O3, it is shown that the ions of Al3+ and O2- are kept close due to the activity of the strong electrostatic ionic bonds. The electrostatic forces and the ionic bonding between the ions are extremely robust due to the presence of the ions high charge density. Therefore, to dissociate the bonds, an enormous amount of energy is needed, and at the same time, a high amount of lattice energy is present.

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3 years ago

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Vlad1618 [11]

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3 years ago

Which of the following statements is false?

natka813 [3]

Answer:

Explanation:

I think B is false because you should communicate with all sorts of people, in order to learn different views/sides of something.

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3 years ago

Jane is sliding down a slide. What kind of motion is she demonstrating?

svp [43]

It is translational motion. i know because i found it on this site. its verified too, have a nice day

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3 years ago

Read 2 more answers

7 f Find the volume in dm3 and in mole of 0.505m of NaoH required to react with 40ml of 0.505m

Anna [14]

The volume of NaOH required is 0.08 dm³

To solve this question, we'll begin by writing the balanced equation for the reaction between H₂SO₄ and NaOH. This is illustrated below:

H₂SO₄ + 2NaOH —> Na₂SO₄ + 2H₂O

From the balanced equation above,

Mole ratio of the acid, H₂SO₄ $(n_{A}) = 1$

Mole ratio of the base, NaOH $(n_{B}) = 2$

Next, we shall determine the volume of NaOH required to react with H₂SO₄. This can be obtained as follow:

Molarity of the base, NaOH $(M_{B}) = 0.505 M$

Volume of the acid, H₂SO₄ $(V_{A}) = 40 mL$

Molarity of the acid, H₂SO₄ $(M_{A}) = 0.505 M$

<h3>Volume of the base, NaOH $(V_{B})$ =? </h3>

$\frac{M_{A} * V_{A}}{M_{B} * V_{B}} = \frac{n_{A}}{n_{B}}\\\\\frac{0.505 * 40}{0.505 *V_{B}} = \frac{1}{2}\\\\\frac{20.2}{0.505 *V_{B}} = \frac{1}{2}$