Answer:
0.0821 L•atm/mol•K
Explanation:
The value of the ideal gas can be obtained as follow:
NOTE: We shall use the standard value for each variable. Based on the options given above, we shall use the equivalent units as well.
Pressure (P) = 1 atm
Volume (V) = 22.4 L
Number of mole = 1 mole
Temperature (T) = 273 K
Gas constant (R) =?
PV = nRT
Divide both side by nT
R = PV / nT
R = (1 × 22.4) / (1 × 273)
R = 22.4 / 273
R = 0.0821 L•atm/mol•K
Thus, the ideal gas constant is 0.0821 L•atm/mol•K
Answer: when you burn something every action has a reaction. so if you put wood in the fire the wood would burn up into this coal like block once completely burnt through. after there is no more wood left to burn the fire would slowly die and there would just be the remains of the wooden block.
When y equals 5, x is 104.3
When y equals 3 then x is 108.3
<em><u>Solution:</u></em>
<em><u>Given expression is:</u></em>
<h3><u>If y equals 5 what is x ?</u></h3>
Substitute y = 5 in given expression
5 = 57.15 - 0.5(x)
5 = 57.15 - 0.5x
0.5x = 57.15 - 5
0.5x = 52.15
Divide both sides by 0.5
x = 104.3
Thus when y equals 5, x is 104.3
<h3><u>If y = 3 what is x ?</u></h3>
Substitute y = 3 in given expression
3 = 57.15 - 0.5(x)
3 = 57.15 - 0.5x
0.5x = 57.15 - 3
0.5x = 54.15
Divide both sides by 0.5
x = 108.3
Thus when y equals 3 then x is 108.3
Answer:
If I'm correct the answer is C. Stay a gas but my gut is telling me the answer is B. turn to a liquid
Answer:
H₃PO₄ is an acid because donates the proton to fenolate.
Fenolate is the base because accepts the proton from the acid.
Explanation:
Bronsted theory mentioned that acid is the one that donates a proton to another compound and base is the one that receives it.
H₃PO₄ + C₆H₅O⁻ ⇄ H₂PO₄⁻ + C₆H₅OH
acid base conj. base conj. acid
H₃PO₄ is an acid because donates the proton to fenolate.
Fenolate is the base because accepts the proton from the acid.
If we follow the dissociation, the diacid phosphate can donate two more protons, it is still a Bronsted acid, but it can act as an acid or a base. This is called amphoteric.