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3 years ago

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Find the value of given expression

20" id="TexFormula1" title=" \sqrt{9 \times 81 \times 9} " alt=" \sqrt{9 \times 81 \times 9} " align="absmiddle" class="latex-formula">

2 answers:

Kay [80]3 years ago

7 0

Answer:

√{9×81×9}=√(9²×9²)=±(9×9)=±81

Furkat [3]3 years ago

5 0

Answer:

your answer will be 81

Step-by-step explanation:

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In ΔABC, ∠B measures 35° and the values of a and b are 19 and 11, respectively. Find the remaining measurements of the triangle,

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Answer:

a) ∠A = 82.2° , ∠C = 62.8° , c = 17.01

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i)</em></u>:-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

<em>By using sine rule </em>

<em></em> $\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C} = 2 R$ <em></em>

now we will use

$\frac{a}{sin A} = \frac{b}{sin B}$

$\frac{19}{sin A} = \frac{11}{sin 35}$

cross multiplication , we get

$\frac{19 X sin 35}{11} = sinA$

<em>sin A = 0.990</em>

<em>A = sin⁻¹( 0.990) = 82.2°</em>

<em> ∠A = 82.2°</em>

<u><em>Step(ii):-</em></u>

we know that ∠A +∠B +∠C = 180°

∠C = 180° - ∠A -∠B

∠C = 180° -82.2°-35°

∠C = 62.8°

<u><em>Step(iii)</em></u>:-

<em>we will use formula</em>

<em></em> $\frac{b}{sin B} = \frac{c}{Sin C}$ <em></em>

<em></em> $\frac{11}{sin 35} = \frac{c}{Sin 62.8}$ <em></em>

$\frac{11 X sin (62.8)}{sin 35} = C$

<em>c = 17.01</em>

<u><em>Final answer</em></u>:-

<em> ∠A = 82.2° , ∠C = 62.8° , c = 17.01</em>

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