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3 years ago

how much centripetal force is needed to make a body of mass 0.5 kg to move in a circle of radius 50 cm with a speed 3ms-1

Physics

2 answers:

Alex17521 [72]3 years ago

6 0

Answer:

9 N

Explanation:

The centripetal force F is F = mrω^2 = (mv^2)/r where m is mass, r is radius of the curve, ω is angular velocity and v is tangential velocity.

In this case, m = 0.5kg, r = 0.5m, v = 3m/s

So F = [0.5kg(3m/s)^2]/0.5m = 9kg-m/s^2 which is 9N

Lelu [443]3 years ago

4 0

Answer:

Explanation:

F = (mv^2)/r

= (0.5 × 3^2) / 50×10^-2

= 9N

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To solve this problem we will apply the concepts related to the balance of forces. Said balance will be given between buoyancy force and weight, both described as derived from Newton's second law, are given as

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Here,

V = Volume

$\rho$ =Density of air

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m = mass

g = Gravity

Our values are given as,

$\text{Weight of the sphere} = W = 0.34 N$

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$\text{gravity}= g = 9.8 m/s^2$

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$F = V\rho g$

Replacing,

$F = (13*10^{-6}m^3 )(1.29Kg/m^3)( 9.8 m/s^2) = 1.6434* 10^{-4} N$

Now net force is ,

$F_{net} = mg - F$

Mass of the sphere is

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Now acceleration of the sphere is

$a = \frac{F_{net}}{m}$

$a = \frac{( 0.34 N)- (1.6434* 10^{-4} N)}{0.03469 kg}$

$a = 9.822m/s^2$

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3 years ago

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Nostrana [21]

Answer:

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(C) is correct option.

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