Answer:

Explanation:
Given data
time=0.530 h
Average velocity Vavg=19.0 km/s
To find
Displacement Δx
Solution
The Formula for average velocity is given as

Answer:
the final speed of object A changed by a factor of
= 0.58
the final speed of object B changed by a factor of
= 1.29
Explanation:
Given;
kinetic energy of object A, = 27 J
let the mass of object A = 
then, the mass of object B = 
work done on object A = -18 J
work done on object B = -18 J
let
be the initial speed
let
be the final speed
For object A;


Thus, the final speed of object A changed by a factor of
= 0.58
To obtain the change in the final speed of object B, apply the following equations.


Thus, the final speed of object B changed by a factor of
= 1.29
A.kinetic energy for it an example of wood.
The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)
Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation
v = vo + at
When you plug in the values you get
v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
The centripetal force experienced by the towel is 55 N.
The given parameters;
- angular speed of the washing machine, ω = 200 rpm
- radius of the machine' drum, r = 0.5 m
- mass of the towel, m = 0.25 kg
The centripetal force experienced by the towel spinning along the walls of the drum is calculated as follows;
Fc = mrω²
where;
<em>Fc is the centripetal force</em>
<em>ω is angular speed in rad/s</em>
The angular speed in rad/s is calculate as;

The centripetal force experienced by the towel is calculated as;

Thus, the centripetal force experienced by the towel is 55 N.
Learn more here: brainly.com/question/20905151