During a lab exam a student looked through the microscope and identified the following cell parts: circular DNA, ribosomes, cell
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Answer:
30 kJ
Explanation:
Arrhenius equation is given by:
Here, k is rate constant, A is Pre-exponential factor, Ea is activation energy and T is temperature.
taking natural log of both side
ln k = ln A - Ea/RT
In Arrhenius equation, A, R and T are constant.
Therefore,
is the lowering in activation energy by enzyme,
R = 8.314 J/mol.K
T = 37°C + 273.15 = 310 K