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Pavel [41]
2 years ago
11

During a lab exam a student looked through the microscope and identified the following cell parts: circular DNA, ribosomes, cell

wall, and cytoplasm. What type of cell did she identify?
Eukaryotic

Endoplasmic

Prokaryotic

None of the above
Chemistry
1 answer:
notsponge [240]2 years ago
5 0

Answer:

The correct answer to this question is a prokaryotic cell.

Explanation:

Prokaryotes have circular DNA and a cell wall, whereas eukaryotes have their DNA packaged into chromosomes and may not have a cell wall (as is the case in animal cells).

Hope this helps!

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Hafnium has six naturally occurring isotopes: 0.16% of 174Hf, with an atomic weight of 173.940 amu; 5.26% of 176Hf, with an atom
ser-zykov [4K]

Answer:

177.277amu

Explanation:

the total occuring isotopes for Hafnium is =6.

First isotope had an atomic weight of 173.940amu

Second isotope =175.941amu

Third isotope =176.943amu

Fourth isotope=177.944amu

Fifth isotope. =178.946amu

sixth isotope .179.947amu

<em>Avera</em><em>ge</em><em> </em><em>ato</em><em>mic</em><em> </em><em>wei</em><em>ght</em><em> </em><em>of</em><em> </em><em>Haf</em><em>nium</em><em>=</em><em> </em><em>sum</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>the </em><em>atomi</em><em>c</em><em> </em><em>weights</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>iso</em><em>topes</em><em>/</em><em> </em><em>Tota</em><em>l</em><em> </em><em>occu</em><em>ring</em><em> </em><em>isotopes</em>

Thus, 173.940amu+175.941amu+176.943amu+177.944amu+178.946amu+179.947amu.= 1063.661amu

Average atomic weight= 1063.661amu /6 = 177.2768333amu

= 177.277amu to 3 decimal places.

6 0
2 years ago
The acetylene tank contains 35.0 mol C2H2, and the oxygen tank contains 84.0 mol O2.
harkovskaia [24]

Answer:- As per the question is asked, 35.0 moles of acetylene gives 70 moles of carbon dioxide but if we solve the problem using the limiting reactant which is oxygen then 67.2 moles of carbon dioxide will form.

Solution:- The balanced equation for the combustion of acetylene is:

2C_2H_2(g)+5O_2(g)\rightarrow 4CO_2(g)+2H_2O(g)

From the balanced equation, two moles of acetylene gives four moles of carbon dioxide. Using dimensional analysis we could show the calculations for the formation of carbon dioxide by the combustion of 35.0 moles of acetylene.

35.0molC_2H_2(\frac{4molCO_2}{2molC_2H_2})

= 70molCO_2

The next part is, how we choose 35.0 moles of acetylene and not 84.0 moles of oxygen.

From balanced equation, there is 2:5 mol ratio between acetylene and oxygen. Let's calculate the moles of oxygen required to react completely with 35.0 moles of acetylene.

35.0molC_2H_2(\frac{5molO_2}{2molC_2H_2})

= 87.5molO_2

Calculations shows that 87.5 moles of oxygen are required to react completely with 35.0 moles of acetylene. Since only 84.0 moles of oxygen are available, the limiting reactant is oxygen, so 35.0 moles of acetylene will not react completely as it is excess reactant.

So, the theoretical yield should be calculated using 84.0 moles of oxygen as:

84.0molO_2(\frac{4molO_2}{5molO_2})

= 67.2molCO_2

7 0
3 years ago
Read 2 more answers
When blood passes through the lungs, carbon dioxide and water are formed from carbonic acid dissolved in the blood. The carbon d
NeTakaya
Answer is: <span>decomposition.

Balanced chemical reaction: H</span>₂CO₃ → CO₂ + H₂O.
H₂CO₃ is carbonic acid.
CO₂ is carbon (IV) oxide or carbon dioxide.<span>
Chemical decomposition is the separation of a single chemical compound (in this example </span>carbonic acid<span>) into its two or more simpler compounds (in this example water and carbon dioxide).</span>
7 0
3 years ago
Read 2 more answers
In your opinion, why do you think the atomic models are not final?
julia-pushkina [17]

Answer:

because they change

Explanation:

It was based on theories and discoveries

7 0
2 years ago
What type of solid is this? This solid has high melting point, does not conduct electricity, and does not dissolve in water. Met
vivado [14]
The awnser It is iconic
5 0
3 years ago
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