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Crank
3 years ago
8

Air that has been removed from a bell jar will NOT allow _____________ waves to travel through the jar. Question 4 options: soun

d light water
Chemistry
1 answer:
White raven [17]3 years ago
3 0

Answer:

Sound.

Explanation:

Sound requires a medium such as air to travel.

You might be interested in
A sample of pure calcium fluoride with a mass of 15.0 g contains 7.70 g of calcium. How much calcium is contained in 40.0 g of c
Temka [501]

Answer:

20.53 g.

Explanation:

  • Knowing that every 15.0 g of pure calcium fluoride contains 7.70 g of calcium.

<u>Using cross multiplication:</u>

15.0 g of pure calcium fluoride contains → 7.70 g of calcium.

40.0 g of pure calcium fluoride contains → ??? g of calcium.

<em>∴ The mass of Ca in 40.0 g of calcium fluoride</em> = (7.70 g)(40.0 g)/(15.0 g) = <em>20.53 g.</em>

6 0
3 years ago
A chemical reaction that gives off heat as it proceeds is said to be:.
Dafna1 [17]
Exothermic.

To remember this, ‘exo’ means outside, and ‘thermic’ means heat. It gives the outside (exo), heat (thermic).
7 0
3 years ago
Use the ideal gas law to calculate the pressure in atmospheres of 0.21 mol of helium (He) at 16°C &amp; occupying 2.53 L. You mu
chubhunter [2.5K]

Answer:

The answer to your question is 2.32 atm

Explanation:

Data

P = ?

n = 0.214

V = 2.53 L

T = 61°C

R = 0.082 atm L/mol°K

Formula

PV = nTR

solve for P

P = nRT/V

Process

1.- Calculate the temperature in K

°K = °C + 273

°K = 61 + 273

    = 334

2.- Substitution

P = (0.214 x 0.082 x 334) / 2.53

3.- Simplification

P = 5.86/2.53

4.- Result

P = 2.32 atm

4 0
3 years ago
Which of the following is a compound? <br><br> Select one:<br> a. Cl2<br> b. H2O<br> c. He<br> d. H2
user100 [1]

I believe the correct answer is B

3 0
4 years ago
How many litres of fluorine gas at stp can be collected from the decomposition of 90.7 g of AuF3
7nadin3 [17]

Answer: 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of AuF_3

Explanation:

The balanced decomposition reaction is shown as

2AuF_3\rightarrow 2Au+3F_2

moles of AuF_3=\frac{\text {given mass}}{\text {Molar mass}}=\frac{90.7g}{254g/mol}=0.36moles

According to stoichiometry:

2 moles of AuF_3 gives = 3 moles of flourine gas

Thus 0.36 moles of AuF_3 gives = \frac{3}{2}\times 0.36=0.54moles of flourine gas

Using ideal gas equation :

PV=nRT

P = pressure of gas = 1 atm ( at STP)

V = Volume of gas = ?

n = moles of gas = 0.54

R = gas constant = 0.0821 L atm/Kmol

T = temperature = 273 K ( at STP)

Putting the values we get :

1atm\times V=0.54mol\times 0.0821Latm/Kmol\times 273K

V=12L

Thus 12 L fluorine gas at STP can be collected from the decomposition of 90.7 g of AuF_3

6 0
3 years ago
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