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Leni [432]
2 years ago
8

What is the half-life in minutes of a compound if 75.0 percent of a given sample decomposes in 40.0 minutes? Assume first-order

kinetics.
Chemistry
1 answer:
yaroslaw [1]2 years ago
8 0

Answer:

See below

Explanation:

.75 = 1/2^(40/h)      

log .75 / ( log 1/2) = 40 / h

<u>h = half life =   96.37683 min</u>

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Answer : There are mainly three isotopes of magnesium found in nature; namely Mg-24, Mg-25 and Mg-26. Out of which Mg-24 has 12 neutrons, Mg-25 has 13 neutrons and Mg-26 has 14 neutrons in their atoms. The number of protons and their atomic masses remains the same for the atom. The relative abundance in nature differs for all the three isotopes. Mg-24 has abundance nearly 80% in nature, Mg-25 has abundance as 10% and Mg-26 has 11.01% abundance.

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A 3.90L sample of gas at STP is cooled to -55oC at 808mmHg. What is the new volume?
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Answer:

3.72L

Explanation:

Given parameters:

Initial volume V₁ = 3.9L

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Final temperature T₂ = -550°C

Final pressure P₂  = 880mmHg

Unknown:

Final volume V₂  = ?

Solution.

At standard temperature and pressure(STP), the:

           Pressure  = 1atm   = 760mmHg

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The general gas law, is best to solve this problem. It is mathematically given as:

           \frac{P_{1} V_{1} }{T_{1} }   = \frac{P_{2} V_{2} }{T_{2} }

Let us take the units to the appropriate one;

      -550°C  = 273 + (-550) = -277K

Input the variables;

             \frac{760 x 3.9}{273}  = \frac{808 x V_{2} }{-277}

        V₂  = 3.72L

           

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