1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Genrish500 [490]
4 years ago
7

Which question must be answered to complete the table below?

Chemistry
1 answer:
I am Lyosha [343]4 years ago
8 0
I need more details so I can answer it for you
You might be interested in
A 1300 mL sample of gas with a molar mass of 71.0 g/mol at STP has what density?
Blizzard [7]

Answer:

0.055g/mL

Explanation:

Data obtained from the question include:

Molar Mass of the gass sample = 71g/mol

Volume of the gas sample = 1300 mL

Density =?

The density of a substance is simply mass per unit volume. It is represented mathematically as:

Density = Mass /volume.

With the above equation, we can easily obtain the density of sample of gas as illustrated below:

Density = 71g / 1300 mL

Density = 0.055g/mL

Therefore, the density of the gas sample is 0.055g/mL

6 0
3 years ago
What do YOU think? Is the movement to 100% renewable energy possible? Why, or why not?
NARA [144]

Answer:

i dont know

Explanation:

ask your science teacher

3 0
3 years ago
If I have 7.0 x 10^24 formula units of magnesium chloride, how many grams of chlorine would I have?
REY [17]

Answer:

824 g

Explanation:

First we <u>convert 7.0 x 10²⁴ formula units of magnesium chloride (MgCl₂) into moles</u>, using <em>Avogadro's number</em>:

  • 7.0 x 10²⁴ formula units ÷ 6.023x10²³ formula units/mol = 11.62 mol MgCl₂

There are two Cl moles per MgCl₂ moles, meaning that we have (2 * 11.62) 23.24 moles of Cl

Finally we <u>convert 23.24 moles of chlorine into grams</u>, using <em>chlorine's molar mass</em>:

  • 23.24 mol * 35.45 g/mol = 824 g
3 0
3 years ago
BaO2(s) + 2HCl(aq) → H2O2(aq) + BaCl2(aq) What mass of hydrogen peroxide should result when 1.50 g barium peroxide is treated wi
Solnce55 [7]

Answer:

mass H2O2 = 0.31g H2O2

mass unreacted = 0.0745g BaO2

Explanation:

Mw BaO2 = 169.33 g / mol

Mw HCl = 36.46 g/mol

Mw H2O2 = 34.0147 g/mol

LR:

⇒ mol BaO2 = 1.50g BaO2 * mol / 169.33 g = 8.86E-3 mol BaO2 / 1 = 8.86E-3 mol BaO2

⇒ mol HCl = 25.0 mL * 0.0272g / mL * mol / 36.46g = 0.0186 mol HCl / 2 = 9.3E-3 mol HCl.....L.R

mol H2O2:

⇒ 0.0186mol HCl * (mol H2O2 / 2mol HCl) = 9.325E-3 mol H2O2

⇒ g H2O2 = 9.325E-3mol H2O2 * 34.0147g H2O2 / mol H2O2 = 0.31g H2O2

mass of wich reagent is left unreacted:

mol that react BaO2 = 0.0186mol HCl * (mol BaO2 / 2mol HCl) = 9.3E-3mol BaO2

mol that unreacted BaO2 = 9.3E-3 - 8.86E-3 = 4.4E-4 mol BaO2

g unreacted BaO2 = 4.4E-4mol BaO2 * (169.33g BaO2 / mol BaO2) = 0.0745g BaO2

8 0
3 years ago
In the reaction below, if a total of 10.0 g of zinc and hydrochloric acid react completely, what is the total mass of zinc chlor
Sloan [31]

Answer:

Not enough information to tell.

Explanation:

What is given?

Mass of Zn = 10.0 g,

Mass of HCl = 10.0 g,

Molar mass of Zn = 65.4 g/mol,

Molar mass of HCl = 36.4 g/mol,

Molar mass of ZnCl2 = 136.2 g/mol,

Molar mass of H2 = 2 g/mol.

Step-by-step solution:

First, let's convert 10.0 g of each reactant to moles using their respective molar mass:

\begin{gathered} 10.0\text{ g Zn}\cdot\frac{1\text{ mol Zn}}{65.4\text{ g Zn}}=0.153\text{ moles Zn,} \\  \\ 10.0\text{ g HCl}\cdot\frac{1\text{ mol HCl}}{36.4\text{ g HCl}}=0.275\text{ moles HCl.} \end{gathered}

Now, let's identify what is the limiting reactant. Let's see how many moles of ZnCl2 can be produced by 0.153 moles of Zn if 1 mol of Zn reacted produces 1 mol of ZnCl2, and how many moles of ZnCl2 can be produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of ZnCl2:

\begin{gathered} 0.153\text{ moles Zn}\cdot\frac{1\text{ mol ZnCl}_2}{1\text{ mol Zn}}=0.153\text{ moles ZnCl}_2, \\  \\ 0.275\text{ moles HCl}\cdot\frac{1\text{ mol ZnCl}_2}{2\text{ moles HCl}}=0.138\text{ moles ZnCl}_2. \end{gathered}

You can realize that the limiting reactant, in this case, is HCl because is the first reactant consumed first and this reactant 'impose' the limit to produce the products.

So now, let's find how many moles of H2 are being produced by 0.275 moles of HCl if 2 moles of HCl reacted produces 1 mol of H2:

0.275\text{ moles HCl}\cdot\frac{1\text{ mol H}_2}{2\text{ moles HCl}}=0.138\text{ moles H}_2.

The final step is to convert each number of moles of each product to grams using their respective molar mass, as follows:

\begin{gathered} 0.138\text{ moles ZnCl}_2\cdot\frac{136.2\text{ g ZnCl}_2}{1\text{ mol ZnCl}_2}=18.8\text{ g ZnCl}_2, \\  \\ 0.138\text{ moles H}_2\cdot\frac{2\text{ g H}_2}{1\text{ mol H}_2}=0.276\text{ g H}_2. \end{gathered}

We're producing 18.8 g of zinc chloride (ZnCl2), and 0.276 g of hydrogen (H2), so based on this logic the answer would be not enough information to tell.

5 0
1 year ago
Other questions:
  • Scientists utilize models for a variety of different purposes, but each type of scientific model has limitations. What might be
    7·1 answer
  • "how many grams of calcium are consumed when 156.8 ml of oxygen"
    14·1 answer
  • Plz help ill give brainlist to you
    6·1 answer
  • Which of the following is true for balancing equations? A. The number of products should be equal to the number of reactants. B.
    9·2 answers
  • Which equation is a decomposition reaction? Li2CO3 Right arrow. Li2O + CO2 Zn + HCl Right arrow. ZnCl2 + H2 Na2O + CO2 Right arr
    10·1 answer
  • ¿Qué es un enlace químico?
    10·1 answer
  • what is the molar ratio between oxygen and carbon dioxide, given the following equation? 2C4H10 + 13O2 right arrow 8CO2 + 10H2O
    12·2 answers
  • Mechanical advantage is the ratio of . Efficiency is the ratio of expressed as a percentage.
    5·2 answers
  • 10 points please please help
    11·1 answer
  • Find the "natural" equilibrium concentration of NO in air in units of molecules/cm3 .
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!