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serg [7]
2 years ago
13

Fill in the blank Cells break down sugar and release ___________ into the plant.

Chemistry
1 answer:
katrin2010 [14]2 years ago
8 0

Answer:

oxygen

Explanation:

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Which of the following is considered a transition metal?
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Sort these species into isoelectronic groups. It doesn\'t matter which group goes in which box, so long as the correct species a
OleMash [197]

Answer : The isoelectronic groups are:

He,Be^{2+},Li^{+}

N^{3-},Mg^{2+}

S^{2-},Ti^{4+},K^{+}

Explanation :

Isoelectronic : It is defined as the compound or molecule having the same number of electrons and the same number of electronic structure.

  • The element is helium. The number of electrons are 2.
  • The element is beryllium. The number of electrons are 4. The number of electrons in Be^{2+} = 4 - 2 = 2
  • The element is lithium. The number of electrons are 3. The number of electrons in Li^{+} = 3 - 1 = 2
  • The element is nitrogen. The number of electrons are 7. The number of electrons in N^{3-} = 7 + 3 = 10
  • The element is neon. The number of electrons are 10.
  • The element is sulfur. The number of electrons are 16. The number of electrons in S^{2-} = 16 + 2 = 18
  • The element is magnesium. The number of electrons are 12. The number of electrons in Mg^{2+} = 12 - 2 = 10
  • The element is titanium. The number of electrons are 22. The number of electrons in Ti^{4+} = 22 - 4 = 18
  • The element is potassium. The number of electrons are 19. The number of electrons in K^{+} = 19 - 1 = 18

The isoelectronic groups are:

He,Be^{2+},Li^{+}

N^{3-},Mg^{2+}

S^{2-},Ti^{4+},K^{+}

7 0
2 years ago
In which level of organization would the roots of a plant most likely be classified make sure to explain too
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Answer:

the biological levels of organization of living things arranged from the simplest to most complex are organelle , cells , tissues , organs , organ system , organism , population , communities , ecosystem , and biosphere....

Explanation:

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Which of the following statements is true?
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A water solution contains 1.704 [kg] of HNO3 per [kg] of water, and has a specific gravity of 1.382 at 20 [°C]. Please, express
Rudik [331]

Answer:

(a) The weight percent HNO3 is 63%.

(b) Density of HNO3 = 111.2 lb/ft3

(c) Molarity = 13792 mol HNO3/m3

Explanation:

(a) Weight percent HNO3

To calculate a weight percent of a component of a solution we can express:

wt = \frac{mass \, of \, solute}{mass \, of \, solution}=\frac{mass\,HNO_3}{mass \, HNO_3+mass \, H_2O}\\  \\wt=\frac{1.704}{1.704+1} =\frac{1.704}{2.704}= 0.63

(b) Density of HNO3, in lb/ft3

In this calculation, we use the specific gravity of the solution (1.382). We can start with the volume balance:

V_s=V_{HNO3}+V_w\\\\\frac{M_s}{\rho_s}=\frac{M_{HNO3}}{\rho_{HNO3}}+\frac{M_w}{\rho_w}\\\\\frac{M_{HNO3}}{\rho_{HNO3}} = \frac{M_s}{\rho_s}-\frac{M_w}{\rho_w}\\\\\rho_{HNO3}=\frac{M_{HNO3}}{\frac{M_s}{\rho_s}-\frac{M_w}{\rho_w}} \\\\ \rho_{HNO3}=\frac{1.704}{\frac{2.704}{1.382*\rho_w}+\frac{1}{\rho_w}} \\\\ \rho_{HNO3}=\frac{1.704}{2.956/ \rho_w}= 0.576*\rho_w[tex]V_s=V_{HNO3}+V_w\\\\\frac{M_s}{\rho_s}=\frac{M_{HNO3}}{\rho_{HNO3}}+\frac{M_w}{\rho_w}\\\\\frac{M_{HNO3}}{\rho_{HNO3}} = \frac{M_s}{\rho_s}-\frac{M_w}{\rho_w}\\\\\rho_{HNO3}=\frac{M_{HNO3}}{\frac{M_s}{\rho_s}-\frac{M_w}{\rho_w}} \\\\ \rho_{HNO3}=\frac{1.704}{\frac{2.704}{1.382*\rho_w}-\frac{1}{\rho_w}} \\\\ \rho_{HNO3}=\frac{1.704}{0.956/\rho_w}= 1.782*\rho_w

The density of HNO3 is 1.782 times the density of water (Sp Gr of 1.782). If the density of water is 62.4 lbs/ft3,

\rho_{HNO3}= 1.782*\rho_w=1.782*62.4 \, lbs/ft3=111.2\, lbs/ft3

(c) HNO3 molarity (mol HNO3/m3)

If we use the molar mass of HNO3: 63.012 g/mol, we can say that in 1,704 kg (or 1704 g) of HNO3 there are  1704/63.012=27.04 mol HNO3.

When there are 1.704 kg of NHO3 in solution, the total mass of the solution is (1.704+1)=2.704 kg.

If the specific gravity of the solution is 1.382 and the density of water at 20 degC is 998 kg/m3, the volume of the solution is

Vol=\frac{M_{sol}}{\rho_{sol}}=\frac{2.704\, kg}{1.382*998 \, kg/m3} = 0.00196m3

We can now calculate the molarity as

Molarity HNO_3=\frac{MolHNO3}{Vol}=\frac{27.04mol}{0.00196m3}  =13792 \frac{molHNO3}{m3}

8 0
2 years ago
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