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3 years ago

On which planet would a spaceship need the largest force to take off

2 answers:

7 0

Weight = mass * gravitational field strength
W = mg

The force to lift off is the force to overcome the force of weight.

As the mass doesn't change, the only variable affecting W is g, the gravitational field strength.

Which planet has the highest gravitational field strength, and that is your answer. (you probably have this in a data book or something, for reference, earth's gravitational field strength is 9.81 ms^-2 , sometimes simplified to 9.8 or 10)

olchik [2.2K]3 years ago

7 0

In the planet of Jupiter because their is more gravity

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Write the word equation, balanced symbol equations and ionic equation got magnesium carbonate

Finger [1]

Explanation:

Mg-2+C+4>Mg2C.

Here you divide the four by the two and transfer the two toMg. In reactions like this oxidation numbers are exchanged.

7 0

3 years ago

The position of a particle moving along an x axis is given by x = 14.0t2 - 2.00t3, where x is in meters and t is in seconds. det

Mumz [18]

a) x = $14t^{2} -2t^{3}$

at t = 5s

$x = 14*5^{2} -2*5^{3} = 14*25 - 2*125 = 350 - 250 = 100 m$

b) v = $\frac{dx}{dt}$

= $28t - 6t^2$

at t = 5 s

v = $28*5-6*25 = 140 - 150 = -10 m/s$

c) a = $\frac{dv}{dt}$

= 28 - 12t

at t = 5 s

a = 28 -12*5= 28-60= -32 m/ $s^2$

d) At maximum positive coordinate velocity = 0

So, $0 = 28t - 6t^2$

$t = \frac{28}{6} = \frac{14}{3} = 4.66 s$

At t = 4.66 s

$X = 14 * 4.66^2 - 2* 4.66^3 = 202.39 m$

e) At t = 4.66 s

f) At maximum positive velocity a = 0

$0=28-12t$

$t = \frac{28}{12} = \frac{7}{3} = 2.33 s$

At t = 2.33 s

V = $28*2.33- 6*2.33^2= 32.67 m/s$

g) t = 2.33 s

h) When particle is not moving v = 0

So $0= 28t - 6 t^2$

$t = \frac{28}{6} = 4.66 seconds$

At t = 4.66 s

a = $28 - 12 * 4. 66 = -27.93m/s^2$

i) At t = 0s, X =0m

t = 5s, X = 100m

So, Displacement = 100m

Velocity = $\frac{Displacement}{Time} = \frac{100}{5} = 20m/s$

8 0

3 years ago

If a person is walking along at 1.4m/s. How long will it take that person to walk one time around a high school track?

ratelena [41]

Answer:

285.7s

Explanation:

Given parameters:

Speed of the person = 1.4m/s

Unknown:

Time it takes to walk one time round the track = ?

Solution:

The circumference of the track is 400m for a standard pitch.

Now;

Speed = $\frac{distance}{time}$

Time = $\frac{distance }{speed }$

Now insert the parameters;

Time = $\frac{400}{1.4}$ = 285.7s

8 0

3 years ago

What happens to the size of atoms as we go from left to right on the periodic table? T

Lady_Fox [76]

Answer:

Atomic size gradually decreases from left to right across a period of elements.

Explanation:

This is because, within a period or family of elements, all electrons are added to the same shell. However, at the same time, protons are being added to the nucleus, making it more positively charged.

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3 years ago

How many electrons, protons, and neutrons are in chlorine?

Rashid [163]

The element chlorine has 17 electrons, 17 protons and 18 neutrons....<span> In an atom there is an equal number of electrons and protons. The number of neutrons is found by subtracting the atomic number from the mass number ...

Hope it helps !!!</span>

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4 years ago