Answer:
a) 0.9995c
b) 5641MeV
c) 91670 MeV
Explanation:
(a) The speed of approach is given by the formula:

(b) the kinetic energy is given by:
![E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{v^2}{c^2}}}-1]](https://tex.z-dn.net/?f=E_k%3Dm_0c%5E2%5B%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7Bv%5E2%7D%7Bc%5E2%7D%7D%7D-1%5D)
by replacing c=3*10^8m/s, m_0=1.67*10^{-27}kg we obtain:

(c) in the rest frame of the other proton we have:
![E_k=m_0c^2[\frac{1}{\sqrt{1-\frac{u^2}{c^2}}}-1]](https://tex.z-dn.net/?f=E_k%3Dm_0c%5E2%5B%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%5Cfrac%7Bu%5E2%7D%7Bc%5E2%7D%7D%7D-1%5D)
by replacing we get

hope this helps!!
The question is incomplete, the atoms in the third period referred to in the question are shown in the image attached.
Answer:
Cl>Si>Ar
Explanation:
Electron affinity refers to the energy released when an atom accepts electron (s) to form a negative ion. It is a periodic property that shows similar trends as electro negativity.
Considering the atoms in period three given in the question; chlorine will have the most negative value of electron affinity. This owes to the fact that halogens accept electrons easily to form negative ions. Silicon in group 14 shows much less negative value of electron affinity while argon, a noble gas, does not accept electrons at all and has an electron affinity of zero KJMol-1 by standard.
This is the answer just double it
Answer:
m₂ = 3kg
Explanation:
The question wasn't clear about what direction the initial velocity of the second cart was, so I'll assume it was going left at 2.0m/s.
Anyway, this is a conservation of momentum problem. The equation you need to use is the one written in blue. They want you to solve for the mass of the second cart, so do some algebra and rearrange that blue equation in term of m₂.
Now that you have the equation for m₂, plug in all the values given from the question and you'll get 3kg.
The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
The given parameters:
- Magnitude of the vector = 350 N
- Position of the vector = 30⁰ South east
The vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.
- The length of the arrow represents the magnitude of the vector which is 350 N.
- The direction of the arrow indicated by the arrow head represents the position of the vector.
- The position of the vector is 30 degrees South of East.
Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.
Learn more about vector representation here: brainly.com/question/14204873