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Inga [223]
3 years ago
15

Y=x+2, x=5 using substitution method

Mathematics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

hmm  i know :)

Step-by-step explanation:

Bad White [126]3 years ago
7 0

Answer: y=7

Step-by-step explanation: in the question, x = 5. if we put 5 to substitute x, the equation we need to use to find y is 5+2. 5+2=7. hopefully I’m correct :)

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The nearest ten 1202(38)
Advocard [28]

Answer:

1202 is rounded to 1200

38 is rounded to 40

1200(40)= 48,000

7 0
3 years ago
What is the greatest common factor of 44c^5, 22c^3 and 11c^4
Alexxandr [17]

\text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

<em><u>Solution:</u></em>

Given that, we have to find the greatest common factor of 44c^5, 22c^3 , 11c^4

The greatest number that is a factor of two (or more) other numbers.

When we find all the factors of two or more numbers, and some factors are the same ("common"), then the largest of those common factors is the Greatest Common Factor

\underline{\text{ GCF of } 44c^5, 22c^3 , 11c^4 :}

First find the GCF of numbers and then find the GCF of variables and then multiply them together

<em><u>Step 1: GCF of 44, 22 and 11</u></em>

The factors of 11 are: 1, 11

The factors of 22 are: 1, 2, 11, 22

The factors of 44 are: 1, 2, 4, 11, 22, 44

11 is the greatest factor that is common in above three list

Then the greatest common factor is 11

\text{ Step 2: GCF of }c^5, c^3 , c^4

c^5 = c^3 \times c^2\\\\c^3 = c^2 \times c^1 \text{ or } c^3\\\\c^4 = c^3 \times c^1

Thus the greatest common factor is c^3

Step 3: Multiply the GCF of 44, 22, 11 and GCF of c^5, c^3 , c^4

\text{ GCF of } 44c^5, 22c^3 , 11c^4 = 11 \times c^3 = 11c^3

Thus \text{ GCF of } 44c^5, 22c^3 , 11c^4 \text{ is } 11c^3

8 0
3 years ago
What is 15/8 as a mixed number
9966 [12]
It would be equal to 1 7/8
6 0
4 years ago
Read 2 more answers
(temperature) answer answer answer answer answer answer answer answer answer answer answer
Bond [772]

Answer:

100

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How fast is a car going if its mass is 1000 kg and the force acting on it is 154 N?
Phoenix [80]

Answer:

Only external forces affect the motion of a system, according to Newton's first law. ... force applied to a car produces a much smaller acceleration than when ... Newton's second law states that a net force on an object is responsible for its ... A 1.0-kg mass thus has a weight of 9.8 N on Earth and only about 1.7 N on the Moon.

Step-by-step explanation:

Only external forces affect the motion of a system, according to Newton's first law. ... force applied to a car produces a much smaller acceleration than when ... Newton's second law states that a net force on an object is responsible for its ... A 1.0-kg mass thus has a weight of 9.8 N on Earth and only about 1.7 N on the Moon.

3 0
3 years ago
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