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Montano1993 [528]
2 years ago
13

Turn -2x+4y=0 into slope-intercept form

Mathematics
1 answer:
yanalaym [24]2 years ago
3 0
Y=1/2x +0. You add the 2x to the other side, and then divide everything by 4 to have only 1y.
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dentify the property used in this equation: 3 + [7 + (–4)] = (3 + 7) + (– 4) Evaluate the expression above.
Leno4ka [110]

Answer:

associative property with respect to addition and subtraction

3+[7+(-4)]=(3+7)+(-4)

3+[7-4]=10+(-4)

3+3=10-4

6=6

Step-by-step explanation:

i hope it will help you

7 0
2 years ago
How to do this question plz answer ​
Soloha48 [4]

Answer:

(⌐■-■)

Step-by-step explanation:

Add perimeter of a quarter circle with radius 7 cm.

Hope this helps....

Have a nice day!!!!

3 0
3 years ago
Part B please help me
Juliette [100K]
He drinks 0.75 liters of juice each day
or
6/8 liters of juice each day
8 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
Solve the equation: (x − 4)(x − 3) = 0
trasher [3.6K]

Answer:

x=4, x=3

Step-by-step explanation:

This is most often the format taken from the polynomial form of this problem, which is x^2-7x+12, and when it is in this format you just take each set of numbers within each parenthesis and set it to zero, then solve. In this case, x can be equal to either 3 or 4.

8 0
2 years ago
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