Answer:
<h2>
206.67N</h2>
Explanation:
The sum of force along both components x and y is expressed as;
The magnitude of the net force which is also known as the resultant will be expressed as
To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.
Given the position of the object along the x-component to be x = 6t² − 4;
Similarly,
Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N
Both the experimental group and the control group are exposed to the same type of treatment.
Answer:
breaking apart of atoms of certain elements to release rays of energy or particles.
Atoms are the building blocks of elements. However, some atoms have an excessive number of neutrons or protons in their nuclei. This causes an imbalance in the forces that keep them together, resulting in an excessive amount of internal energy. These atoms are referred to as radioactive or unstable.
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Both Distance and displacement deals the distance of the object but they differ distinct is scalr quantity and displacement is vector quantity or have Direction
How dense the medium is in the compression part of the wave and how rare the medium is in the rarefaction part of the wave is a measure of the longitudinal wave's amplitude.