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3 years ago

How much would a 15.0 kg object weigh on Neptune?

Physics

2 answers:

yKpoI14uk [10]3 years ago

6 0

Weight = (mass) · (gravity)

Weight = (15.0 kg) · (11.2 m/s²)

Weight = (15.0 · 11.2) · (kg · m/s²)

Weight = 168 Newtons

yan [13]3 years ago

5 0

The gravity on Neptune is 11.15 m/s²
the gravity on earth is 9.81 m/s²
divide the Neptune and earth gravity we get 1.13
which means object on neptune is 1.13 heavier than earth
yield, weigh of the object on neptune is 1.13×15=17.04kg

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Answer:

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Explanation:

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For the ion of oxygen-16, we have:

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$v_A=2.90\cdot 10^6 m/s$

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For the ion of oxygen-18, we have:

$m_B = \frac{18}{16}m_A = 2.99\cdot 10^{-26}kg$

$q_B = 1.6\cdot 10^{-19}C$ (it is singly charged)

$v_B=2.90\cdot 10^6 m/s$

$B_B=1.30 T$

So the radius of its orbit is

$r_B=\frac{m_B v_B}{q_B B_B}=\frac{(2.99\cdot 10^{-26})(2.90\cdot 10^6)}{(1.6\cdot 10^{-19})(1.30)}=0.417 m$

After each ion has travelled a semicircle, the separation between the two ions will be twice the difference in their radius, so:

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