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dsp73
3 years ago
6

Which method can be used to solve 11x13

Mathematics
2 answers:
pickupchik [31]3 years ago
5 0

Answer:

Use the grid method, since it is the most obvious option. But, you may also use the distribution method.

Step-by-step explanation:

Distribution method:

divide 13 into 10 +3

then multiply 11 with 10 and 3 individually.

This can be written as 11(10+3) = 110+33 = 143

Please mark brainiest

butalik [34]3 years ago
3 0

Answer:

Simple column method

Step-by-step explanation:

  11

x <u>13</u>

  33

 <u>110</u>

 143

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\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})


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\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}


just a quick note on notation:

\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}

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Can anyone solve this please asap​
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Answer:

<h2>= 1.268</h2>

Step-by-step explanation:

= (3 + √3) (2 - √3)

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