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3 years ago

Which method can be used to solve 11x13

Mathematics

2 answers:

pickupchik [31]3 years ago

5 0

Answer:

Use the grid method, since it is the most obvious option. But, you may also use the distribution method.

Step-by-step explanation:

Distribution method:

divide 13 into 10 +3

then multiply 11 with 10 and 3 individually.

This can be written as 11(10+3) = 110+33 = 143

Please mark brainiest

butalik [34]3 years ago

3 0

Answer:

Simple column method

Step-by-step explanation:

x <u>13</u>

143

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What is the distance between (1, -1) and (-2,3) ?

viva [34]

Answer:

the answer is 5

8 0

3 years ago

A man sells a type of nut for $7 per pound and a different one for $4.20 per pound, how much of each type should be used to make

qwelly [4]

Answer:

a type nut is 10 pounds

a different one is 14 pounds

Step-by-step explanation:

let a type of the nut be represented by t

Let a different one be represented by d

a type of nut cost $7 per pound

a different one cost $4.20 per pound

The cost of the mixture for 24 pounds = 5.37 * 24

= $128.88

t + d = 24 ........(1)

7t + 4.2d = 128.88 ..........(2)

From equation (1), t = 24 - d

Put t = 24 - d in equation 2

7(24 - d) + 4.2d = 128.88

168 - 7d + 4.2d = 128.88

168 - 2.8d = 128.88

-2.8d = 128.88 - 168

-2.8d = -39.12

d = -39.12 / -2.8

d= 13.97

d = 14 pounds

t = 24 - d

t = 24 - 14

t = 10 pounds

A type nut is 10 pounds. A different one is 14 pounds

5 0

3 years ago

Read 2 more answers

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$