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dsp73
3 years ago
6

Which method can be used to solve 11x13

Mathematics
2 answers:
pickupchik [31]3 years ago
5 0

Answer:

Use the grid method, since it is the most obvious option. But, you may also use the distribution method.

Step-by-step explanation:

Distribution method:

divide 13 into 10 +3

then multiply 11 with 10 and 3 individually.

This can be written as 11(10+3) = 110+33 = 143

Please mark brainiest

butalik [34]3 years ago
3 0

Answer:

Simple column method

Step-by-step explanation:

  11

x <u>13</u>

  33

 <u>110</u>

 143

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Simplify. 12k - 6 + (3k)(4) Is it -6, 6, 24k + 6, or 24k - 6?
Effectus [21]
It's 24k-6

By order of operations, you do the multiplication first: 3k(4) = 12k

12k-6+12k now combine like terms

24k-6

Hope that helps




7 0
3 years ago
Please help! <br><br> ~I WILL MARK BRAINLIEST!~
likoan [24]
I’m pretty sure it is B
Hope I helped.
6 0
3 years ago
Read 2 more answers
Can someone please help me i will give free 50 points
Grace [21]

Would it be 11 and 12?

6 0
2 years ago
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A pack of red pens can be divided into equal shares among 3, 5, 6 and 9 teachers with no pen left over?
Ugo [173]

Answer:

90 red pens

Step-by-step explanation:

we need to find the least common multiple of the numbers 3 , 5 , 6 , 9

6 = 2 × 3

9 = 3²

then

LCM(3,5,6,9) = 2×5×3² = 2×5×9 = 90

The number 90 can be divided into 3 ,5 ,6 ,9 with no remainder

Therefore the pack must have 90 pens or a multiple of 90

For example 180 , 270 ...

7 0
2 years ago
The graph above is a transformation of the function x2 Write an equation for the function graphed above
lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2)   \ \ \ \  y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \  \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right  \\

We summarize (1) and (3):

2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.

Substitute b=-1 into (2):

9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\

From (5) subtract (4):

8a=4\ |:8\\a=0,5.\ \ \ \  \Rightarrow\\

Substitute a=0,5 into (4):

0,5+c=-1\\c=-1,5.

Hense:

y=0,5x²-x-1,5.

5 0
2 years ago
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