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aleksandrvk [35]
3 years ago
7

Which of the following is correct for adsorption theory of Heterogeneous catalysis? Statement-I : This theory explains why the c

atalyst remains unchanged in mass and chemical composition at the end of the reaction. Statement-II : This theory explains the action of catalytic promoters and catalytic poison.
Statement-I is true, Statement-II is false
Statement-I is false, Statement-II is true
Both Statement-I and Statement-II are true
Both Statement-I and Statement-II are false

please answer rightly
Chemistry
1 answer:
Ostrovityanka [42]3 years ago
3 0

Answer:

The correct answer is - Statement I is true, Statement-II is false.

Explanation:

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5 0
3 years ago
Use the Nernst equation to calculate the concentration of the unknown solution. Base this on your experimental voltage of 1.074
Hoochie [10]

Answer:

0.3793 M

Explanation:

The unknown metal is zinc. So the equation of the reaction is;

Zn(s) + Cu^2+(aq) -------> Zn^2+(aq) + Cu(s)

From Nernst equation;

E = E° - 0.0592/n log Q

[Cu2+] = 0.050179 M

n = 2

[Zn^2+] = ?

E = 1.074 V

E° = 0.34 - (-0.76) = 1.1 V

Substituting values;

1.074  = 1.1 - 0.0592/2 log [Zn^2+]/0.050179

1.074 - 1.1 = - 0.0592/2 log [Zn^2+]/0.050179

-0.026 = -0.0296  log [Zn^2+]/0.050179

-0.026/-0.0296 = log [Zn^2+]/0.050179

0.8784 =log [Zn^2+]/0.050179

Antilog(0.8784) = [Zn^2+]/0.050179

7.558 =  [Zn^2+]/0.050179

[Zn^2+] = 7.558 * 0.050179

[Zn^2+] = 0.3793 M

4 0
3 years ago
Commercial manufacturers produce nitric acid (HNO3) by the Ostwald process. The process requires three steps:
Shkiper50 [21]

Answer:

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Explanation:

5 0
3 years ago
What is the mass of an atom that has 4 protons, 5 neutrons, and 4 electrons?
Mazyrski [523]
The answer would be 9
3 0
3 years ago
Read 2 more answers
Calculate the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remain
Reil [10]

The balanced chemical equation for the production of chromium metal from the reaction of chromium(ll) nitrate reacts with a strip of zinc is:

3 Zn + 2 Cr(NO₃)₃ → 2 Cr + 3 Zn(NO₃)₂

This is a redox reaction, which <u>is a chemical reaction in which one or more electrons are transferred between the reagents</u>, causing a change in their oxidation states. In the proposed reaction, Cr oxidation state goes from +3 to 0, becoming metallic chromium, while Zn goes from being Zn⁰ to Zn²⁺.

<u>The mass of chromium metal produced in the above reaction will be,</u>

425.0 mL x \frac{1 L}{1000 mL} x  \frac{0.25 mol Cr(NO_{3})_{3}  }{1 L} x \frac{2 mol Cr  }{2 mol Cr(NO_{3})_{3} } x \frac{51.9961 g Cr}{1 mol Cr} = 5.52 g

So, the mass of chromium metal produced when 425.0mL of 0.25M chromium(ll) nitrate reacts with a strip of zinc that remains in excess is 5.52 g of Cr.

6 0
3 years ago
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