1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex787 [66]
3 years ago
14

(a) the characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. combustio

n of 4.17 mg of ethyl butyrate produces 9.48 mg of co2 and 3.87 mg of h2o. what is the empirical formula of the compound?
Chemistry
2 answers:
ella [17]3 years ago
8 0

By stoichiometry and assume that:

CxH2xOy + zO2 -> xCO2 + xH2O 

<span>
CO2: 9.48/44 = 0.215 mmol 
H2O: 3.87/18 = 0.215 mmol 
mass of C = 0.215 * 12 = 2.58 mg 
mass of H = 0.215 * 2 * 1 = 0.43 mg 
mass of O in ethylbutyrate = 4.17 - 2.58 - 0.43 = 1.11 mg 
So C/O = 2.58/1.11 ≈ 3 </span>

<span>
Thus we have C3H6O</span>

<span> </span>

natali 33 [55]3 years ago
6 0

Answer: The empirical formula for the given compound is C_3H_6O

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

C_xH_yO_z+O_2\rightarrow CO_2+H_2O

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=9.48mg=9.48\times 10^{-3}g

Mass of H_2O=3.87mg=3.87\times 10^{-3}g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 9.48\times 10^{-3}g of carbon dioxide, \frac{12}{44}\times 9.48\times 10^{-3}=2.58\times 10^{-3}g of carbon will be contained.

For calculating the mass of hydrogen:

In 18 g of water, 2 g of hydrogen is contained.

So, in 3.87\times 10^{-3}g of water, \frac{2}{18}\times 3.87\times 10^{-3}=4.30\times 10^{-4}g of hydrogen will be contained.

For calculating the mass of oxygen:

Mass of oxygen in the compound = (4.17\times 10^{-3})-[(2.58\times 10^{-3})+(4.30\times 10^{-4})]=1.16\times 10^{-3}g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{2.58\times 10^{-3}g}{12g/mole}=2.15\times 10^{-4}moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{4.30\times 10^{-4}g}{1g/mole}=4.30\times 10^{-4}moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.16\times 10^{-3}g}{16g/mole}=7.25\times 10^{-5}moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.25\times 10^{-5} moles.

For Carbon = \frac{2.15\times 10^{-4}}{7.25\times 10^{-5}}=2.96\approx 3

For Hydrogen  = \frac{4.30\times 10^{-4}}{7.25\times 10^{-5}}=5.93\approx 6

For Oxygen  = \frac{7.25\times 10^{-5}}{7.25\times 10^{-5}}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is C_3H_6O_1=C_3H_6O

You might be interested in
Among important crop plants, nitrogen-fixing root nodules are most commonly an attribute of A) corn. B) legumes. C) wheat. D) me
7nadin3 [17]
<span>Among important crop plants, nitrogen-fixing root nodules are most commonly an attribute of
B) legumes</span>
3 0
3 years ago
I WILL GIVE BRAINLIEST TO BEST AND MOST THOROUGH ANSWER!
andrew11 [14]
<span>At 100 feet, the diver is under about 4 atmospheres pressure. If she is free diving, her lungs will be compressed to about 1/4 their size on the surface (with some movement of the major abdominal organs). If she is scuba diving, the air which she is breathing is also at 4 atmospheres and there is no problem. (The non-gas spaces in the body are not-compressible and are unaffected.) The only problems she has to concern herself with are the beginnings to nitrogen narcosis and the nitrogen which is dissolving (Henry's law) into her body tissues. On the way up, she also has to remember that the air in her lungs will expand by a factor of 4 and she better exhale! Hope this helps you</span>
7 0
3 years ago
What refers to the body’s inability to maintain a stable internal environment.
dalvyx [7]
One term could be allostasis, the opposite of homeostasis.

Other antonyms of homeostasis, the body's ability to maintain a stable internal environment, include imbalance, instability, etc.
8 0
3 years ago
Read 2 more answers
The element whose neutral isolated atoms in the ground state have three half filled orbital is
jolli1 [7]
One would be phosporous whose configuration is 1s2 2s2 2p6 3s2 3p3
5 0
3 years ago
aspirin C6H4(CO2)(CO2CH3),can be prepared in the chemistry laboratory by the reactions of salicylic acid, C6H4(CO2H)(OH),with ac
Ket [755]
262mol 1=kg
g=1000
from stoichoimetry

x=102*1000/360
x=102000/360
x=283.33

density =m/v
=283.33/1.082
=262mol

8 0
3 years ago
Other questions:
  • The alkali metals react with the halogens to form ionic metal halides. what mass of potassium chloride forms when 5.11 l of chlo
    11·1 answer
  • the solid above sink to the bottom when you put a container filled with it what does that tell you about density
    14·1 answer
  • What are the uses of an enema? Select all that apply. what are the uses of an enema? select all that apply. ?
    12·1 answer
  • What is the empirical formula of a compound that is 64.3 % c, 7.2 % h, and 28.5 % o by mass?
    5·1 answer
  • What is the chemical symbol for dynamite?
    15·2 answers
  • Which of the following is a chemical property of aluminum?
    8·1 answer
  • For each of the following, highlight the element which has the highest:
    15·1 answer
  • If 125 g of CaCO3 is mixed and reacted with 125 g of HCl, which reactant is limiting and how many grams of CO2 can be made?
    5·1 answer
  • Treading water is used as efficient tool for what?
    5·1 answer
  • 65. Write an equation for the combustion of octane.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!