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3 years ago

A. Give two examples of addition of Like Fractions.

Mathematics

1 answer:

zavuch27 [327]3 years ago

5 0

Answer:

A: 3/5 + 2/5 = 5/5

A: 3/5 + 1/5 = 4/5

B: 3/5 - 2/5 = 1/5

B: 3/5 - 1/5 = 2/5

C: 3/5 x 2/5 = 6/25

C: 3/5 x 1/5 = 3/25

C: 2/5 x 1/5 = 2/25

D: 1/2 + 1/4 = 3/4

D: 4/5 + 4/10 = 6/5

E: 4/6 ÷ 2/6 = 2

E: 1/6 ÷ 1/6 = 1

Step-by-step explanation:

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The sum of two numbers is equal to 11 and the difference is 19. What are the two numbers?

charle [14.2K]

$\bold{\huge{\pink{\underline{ Solution }}}}$

We have given in the question that, 

The sum of 2 numbers is equal to 11
The difference between two numbers is 19 .

$\bold{\underline{ To \: Find }}$

We have to find the value of x and y.

$\bold{\underline{ Let's \: Begin }}$

Let the two numbers be x and y

According to the question, 

$\sf{ x + y = 11......eq(1) }$

$\sf{ x - y = 19......eq(2) }$

Solving eq( 1 ) we get :- 

$\sf{ x + y = 11 }$

$\sf{ x = 11 - y ......eq(3 ) }$

Subsituting eq(3 ) in eq(2) :-

$\sf{ x - y = 19 }$

$\sf{ ( 11 - y) - y = 19 }$

$\sf{ 11 - y - y = 19 }$

$\sf{ 11 - 2y = 19 }$

$\sf{ - 2y = 19 - 11 }$

$\sf{ - 2y = 8}$

$\sf{ y = 8/(-2) }$

$\sf{ y = - 4 }$

$\sf{\red{Thus ,\: the\: value\: of \: y = -4}}$

Now, Subsitute the value of y in eq( 3 ) :-

$\sf{ x = 11 - y }$

$\sf{ x = 11 - (-4 ) }$

$\sf{ x = 11 + 4 }$

$\sf{ x = 15 }$

Hence, The value of x and y are 15 and (-4) .

5 0

3 years ago

Can somebody help me on 23 and 24, it’s geometry

Luda [366]

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

Question number 23:

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

$DS = SE\\3x+10 = 6x-2$

Subtracting 10 from both sides

$3x+10-10 = 6x-2-10\\3x = 6x-12$

subtracting 6x from both sides

$3x -6x = 6x-6x-12\\-3x = -12$

Dividing both sides by -3

$\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4$

Now

$DS = 3x+10\\= 3(4)+10\\= 12+10\\=22$

And

$SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44$

Question No 24:

Given

DS = x+3

DE = 56

We know that:

$DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25$

DS = $25+3 = 28$

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

#LearnwithBrainly

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3 years ago

Write an equation of the function

ohaa [14]

Answer:

g(x) = |x-3| -4

Step-by-step explanation:

to shift right by 3, subtract three from x inside the absolute value.

to shift down by 4, subtract 4 outside of the absolute value.

g(x) = |x-3| -4

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jenyasd209 [6]

Answer:

The Answer Is C

Step-by-step explanation:

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photoshop1234 [79]

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