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3 years ago

What is the probability that a randomly selected student has a cell phone and is from School B?

Mathematics

2 answers:

erastova [34]3 years ago

4 0

Answer:

Step-by-step explanation:

Because there is 1000 people in total, the percentage of people in the school B with cellphones would be solved by finding 408/1000=.408. If you round .408 to the nearest hundredth, because the thousandth place is 8, it would round up to .41

puteri [66]3 years ago

3 0

Answer:

$\huge\boxed{\text{(B)}\ 0.41}$

Step-by-step explanation:

This table will prove to be helpful to find the probability that a student has a cell phone and is from School B.

First off, we know that a total of 1000 students were interviewed, both from School A and from School B.

We also know that 479 of those 1000 were from School B (total on the right).

Looking further into School B, we can see that 408 students from school B have a cell phone.

Therefore, we can find the probability by finding 408 / 1000.

$408 \div 1000 = 0.408 \approx 0.41$

Therefore, the probability that a randomly selected student is from School B and has a phone is 0.41, or 41%.

Hope this helped!

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The equation 6x2 - 132 +5 -0 has solutions of the form

MArishka [77]

Answer:

(A)

$N = -b = -(-13) = 13\\\\$

$D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49$

$M = 2a = 2(6) = 12$

(B)

$x = (\frac{5}{3} , \: \frac{1}{2})$

Step-by-step explanation:

The given equation is

$6x^2 - 13x + 5 = 0$

The solution is of the form as given by

$x=\frac{N\pm\sqrt{D}}{M}$

(A) Use the quadratic formula to solve this equation and find the appropriate integer values of N, M and D. Do not worry about simplifying the VD yet in this part of the problem.

The quadratic formula is given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

The equations of N, M and D are

$N = -b$

$D =b^2 -4ac$

$M = 2a$

The values of a, b and c are

$a = 6 \\\\b = -13 \\\\c = 5$

So,

$N = -b = -(-13) = 13\\\\$

$D =b^2 -4ac = (-13)^2 - 4(6)(5) = 169- 120 = 49$

$M = 2a = 2(6) = 12$

(B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: -5/2-3/4

N = 13

D = 49

M = 12

$x=\frac{13\pm\sqrt{49}}{12}$

$x=\frac{13\pm7}{12}$

$x=\frac{13+7}{12}$ and $x=\frac{13-7}{12}$

$x=\frac{20}{12}$ and $x=\frac{6}{12}$

$x=\frac{5}{3}$ and $x=\frac{1}{2}$

$x = (\frac{5}{3} , \: \frac{1}{2})$

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Answer:

Step-by-step explanation:

A)Initial amount deposited into the account is $6500 This means that the principal is P, so

P = 500

It was compounded daily. This means that it was compounded 360 times in a year. So

n = 360

The rate at which the principal was compounded is 3%. So

r = 3/100 = 0.03

It was compounded for 5 years. So

t = 5

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. Therefore

A = 6500 (1+0.03/360)^360×5

A = 6500 (1+0.00008333333)^360×5

A = 6500 (1.00008333333)^1800

A = $7551.70

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beks73 [17]

Answer:

Step-by-step explanation:

(6)^1/2 × (8)^1/2

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Please ANSWER ASAP!!!!!!! ANSWER FIRST TO GET BRIANLIEST ANSWER!!!!!!!!

Ray Of Light [21]

Surface area
break it down
bottom and top
bottom=5 rectangle
top=2 triangles+2rectangle
areas
area of recatngle=lw
area of traignle=1/2lw

so total is
SA=(8 times 2.8)+(2.8 times 4.8) +(2.8 times 4.8)+(4.8 times 8)+(4.8 times 8)+(5 times 2.8)+(5 times 2.8)+(1/2 times 3 times 8)+(1/2 times 3 times 8)
(I'm not going to do all the math, just the result)
SA=178.08 yd^2

split the figure into 2 parts
top and bottom
bottom=rectagular prism=lwh
top=triangle tingie, wait, if we take 1/2 of it and put it with the other, half, we get a rectangular prism with 1/2 base so

bottom=8 times 2.8 times 4.8=107.52
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ANSWERS
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