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ruslelena [56]
3 years ago
9

What is the probability that a randomly selected student has a cell phone and is from School B?

Mathematics
2 answers:
erastova [34]3 years ago
4 0

Answer:

B

Step-by-step explanation:

Because there is 1000 people in total, the percentage of people in the school B with cellphones would be solved by finding 408/1000=.408. If you round .408 to the nearest hundredth, because the thousandth place is 8, it would round up to .41

puteri [66]3 years ago
3 0

Answer:

\huge\boxed{\text{(B)}\ 0.41}

Step-by-step explanation:

This table will prove to be helpful to find the probability that a student has a cell phone and is from School B.

First off, we know that a total of 1000 students were interviewed, both from School A and from School B.

We also know that 479 of those 1000 were from School B (total on the right).

Looking further into School B, we can see that 408 students from school B have a cell phone.

Therefore, we can find the probability by finding 408 / 1000.

408 \div 1000 = 0.408 \approx 0.41

Therefore, the probability that a randomly selected student is from School B <em>and</em> has a phone is 0.41, or 41%.

Hope this helped!

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a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and
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Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

x(t) = -4.9t^{2} + 9.8t

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format x(t) = at^{2} + bt + c

The vertex is the point (t_{v}, x(t_{v})), in which

t_{v} = -\frac{b}{2a}

In this question:

x(t) = -4.9t^{2} + 9.8t

So a = -4.9, b = 9.8

Vertex:

t_{v} = -\frac{9.8}{2*(-4.9)} = 1

The time taken for the upward motion is 1 second.

x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

-4.9t^{2} + 9.8t = 0

4.9t^{2} - 9.8t = 0

4.9t(t - 2) = 0

4.9t = 0

t = 0

Or

t - 2 = 0

t = 2

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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