1.00mol of oxygen gas has a pressure of 2.50atm at 325K. Use the ideal gas law to determine the volume of the gas.
1 answer:
Answer:
10.66L
Explanation:
The following were obtained from the question:
n = 1 mole
P = 2.5atm
T = 325K
R = 0.082atm.L/Kmol
V =?
Using the ideal gas equation PV = nRT, the volume of the gas can easily be obtain as illustrated below:
PV = nRT
V = nRT/P
V = (1 x 0.082 x 325) /2.5
V = 10.66L
The volume of the gas is 10.66L
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