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3 years ago

14

..can someone answer these questions ive already posted this question 16 times and I dont have much points left so please anyone

can u please answer these questions!

2 answers:

noname [10]3 years ago

7 0

Answer

A
D
D
A
B
A

This is what I got, but i'm mot sure if I'm right

Assoli18 [71]3 years ago

3 0

A D D A B A
Those are all the answers for those questions

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14. All the following are necessary parts of a neutralization reaction except A. an indicator. B. a salt. C. water. D. an acid.

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3 years ago

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit

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Answer:

4 moles, 160 g

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The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

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Mass of $H_2SO_4$ = 196 g

Molar mass of $H_2SO_4$ = 98 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{196\ g}{98\ g/mol}$

$Moles\ of\ Sulfuric\ acid= 2\ mol$

According to the given reaction:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = $4\times 40\ g$ = 160 g</u>

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3 years ago