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Oliga [24]
3 years ago
6

Compare the drops of wax that harden in hot water and Cold water.

Chemistry
1 answer:
juin [17]3 years ago
7 0

Answer: They are are simular because when the wax cools down its not hot  or it cools down it is the same with hot water it cools after along while.

Explanation:

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fgiga [73]
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4 0
3 years ago
All reactions involving a change in temperature are exothermic.<br> a. True<br> b. False
diamong [38]
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8 0
4 years ago
if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g
AnnyKZ [126]
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5 0
3 years ago
A chemical reaction produces 138 mol of HBr gas. What volume will that gas occupy at STP?
stepan [7]

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The second one

Explanation:

5 0
3 years ago
Read 2 more answers
What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha
sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

<u>Given:</u>

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

<u>To determine:</u>

The mean free path, λ

<u>Calculation:</u>

The mean free path is related to the collision cross section by the following equation:

\lambda =\frac{1}{n\sigma }------(1)

where n = number density

n = \frac{P}{kT}-----(2)

Substituting for P, k and T in equation (2) gives:

n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\  m^{3}

Next, substituting for n and σ in equation (1) gives:

\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m

6 0
3 years ago
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