<h3><u>Question:</u></h3>
The formula h = 120t-16t^2 gives the height h in feet of an object t seconds after it is shot upward from Earth's surface with an initial velocity of 120 feet per second. What will the height of the object be after 6 seconds?
<h3><u>Answer:</u></h3>
The height of object after 6 seconds is 144 feet
<h3><u>Solution:</u></h3>
<em><u>The formula that gives the height of an object is:</u></em>
Where,
h is the height in feet and t is the time in seconds
To find: height of the object be after 6 seconds
To find the height of the object be after 6 seconds, substitute t = 6
Thus height of object after 6 seconds is 144 feet
I think the answer would be c but I'm not positive
I hope I help :)
3m^2+2p^2-15
3(3)^2+2(10)^2-15
3(9)+2(100)-15
21+200-15
206
Answer:
a=2.48
c=9.52
Step-by-step explanation:
a+c=12
4a+7.5c=72.5 Given
a+c=12
-4a-7.5c=-72.5 multiply the equation by negative 1
-3a-6.5c=-60.5 simplify
-3a=-60.5+6.5c add 6.5c to both sides
a=-20.17+2.17c divide it by 3
now you would take that equation and plug it into an equation you already have since you have something to plug in for a, the easiest one to do is a+c=12
(-20.17+2.17c)+c=12 plug in the equation
-20.17+3.17c=12 simplify by solving for c
3.17c=30.17 add 20.17 to both sides
c=9.52 divide both sides by 3.17
now since you have found c, you can plug it in to you equation to solve for a now (use the ones from the second step). I am using the equation a+c=12.
a+9.52=12 plug in the variable and solve for a
a=2.48 subtract 9.52 to both sides
a=2.48
c=9.52
140%
Step-by-step explanation:
