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Ronch [10]
3 years ago
10

The slope of a velocity time graph will give___

Physics
1 answer:
nadya68 [22]3 years ago
6 0

Answer:

<h3>THE ANSWER IS <em>(</em><em> </em><em>acceleration of the object</em><em> </em><em>)</em></h3>
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During which phase of mitosis do the chromosomes line up across the center of the cell?
nirvana33 [79]
Metaphase; the centromeres of  duplicated chromosomes line up in the middle of the cell. (It's also the shortest phase of mitosis).
5 0
3 years ago
If the index of refraction of a lens is 1.5, how fast does light travel in the lens?
Len [333]
The speed of light in a material is given by:
v= \frac{c}{n}
where
c=3 \cdot 10^8 m/s is the speed of light in vacuum
n is the refractive index of the material

The lens in this problem has a refractive index of n=1.50, therefore the speed of light in the lens is
v= \frac{c}{n}= \frac{3 \cdot 10^8 m/s}{1.50}=2 \cdot 10^8 m/s

And the correct answer is C).
5 0
3 years ago
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How will the equation of morion for an object moving with an ununifor motion change????? please help me !!!!!!
babymother [125]

Answer:

The equation of motion is derived based on the Newton’s laws of motion. And it changes accordingly when an object changes with uniform velocity.

Given is that object moves with uniform velocity, that is no change in velocity so there will no acceleration.

As we know    

Here, u = v (due to uniform velocity)

.

1st equation of motion is, v = u + at

2nd equation of motion,  

3rd equation of motion,  

.

Explanation:

4 0
3 years ago
At which boundary does subduction stop occurring, resulting in a mountain range?
NARA [144]
Subduction occurs at convergent tectonic plate boundaries, resulting in high rates of volcanism, earthquakes and mountain building.
6 0
3 years ago
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Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 60 mi/h.How
Pachacha [2.7K]

Answer:

The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

Explanation:

Given;

speed of the faster car, v₁ = 60 mi/h

speed of the slower car, v₂ = 55 mi/h

Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles

\frac{x}{55} - \frac{x}{60}   = \frac{15}{60}

Note: divide 15 mins by 60 to convert to hours for consistency in the units.

\frac{x}{55} - \frac{x}{60}   = \frac{15}{60}\\\\multiple \ through \ by \ 660\\\\12x - 11x = 165\\\\x = 165 \ miles

Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

4 0
3 years ago
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