The mass of lead = 22,939 kg
<h3>Further explanation</h3>Given
mass alcohol=1600 kg
The density of lead =11300kg\m³ and density of alcohol=790kg\m³
Required
mass of lead
Solution
the volume of lead=volume of alcohol=2.03 m, so the mass of lead :
Answer:-81.29 J
Explanation:
Given
mass of ball
Length of string
height of Room
Gravitational Potential Energy is given by
where h=distance between datum and object
here Reference is ceiling
therefore
Potential Energy of ball w.r.t ceiling
i.e. 81.29 J of Energy is required to lift a ball of mass 2.35 kg to the ceiling
Answer:
0.004 m
Explanation:
For light passing through a single slit, the position of the nth-minimum in the diffraction pattern is given by
where
is the wavelength
D is the distance of the screen from the slit
d is the width of the slit
Therefore, the width of the central maximum is equal to twice the value of y for n=1 (first minimum):
where we have
is the wavelength
D = 2.0 m is the distance of the screen
is the width of the slit
Substituting, we find