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Luba_88 [7]
3 years ago
7

A carnot engine operates between two heat reservoirs at temperatures th and tc. an inventor proposes to increase the efficiency

by running one engine between th and an intermediate temperature t and a second engine between t and tc using as input the heat expelled by the first engine.
Physics
1 answer:
Sonja [21]3 years ago
5 0
The efficiency of the first Carnot engine is 
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
n = 1 - Th/Tc
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The work done in the isothermal process is 10 joule.

We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.

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Hence,

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Answer:

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Explanation:

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the bold are vectors, where the angle is between the position vector and the velocity, in this case it is 90º therefore the sine is 1

as we have two bodies

       L = 2 r m v

let's find the distance from the center of mass, let's place a reference frame on one of the masses

        x_{cm} = \frac{1}{M} \sum  x_{i} m_{i}i

        x_{cm} = \frac{1}{m+m} ( 0 + l m)

        x_{cm} = \frac{1}{2m}  lm

        x_{cm} = \frac{1}{2}

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let's calculate

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4 0
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