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dem82 [27]
2 years ago
11

Which of the following BEST describes all planets in the universe?

Physics
1 answer:
Harman [31]2 years ago
7 0

Answer:

c large, spherical body that orbits in a clear path around a star

Explanation:

you can not say b because the sun is a star and you cant say a and d because all planets are not made of rock and all planets are not made of gas

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A school bus moves at speed of 35 mi/hr for 20 miles. How long will it take the bus to get to school
ludmilkaskok [199]

Answer:

Explanation:

Assuming school is at the end of the 20 mile route, then

20 mi / 35 mi/hr = 0.57142...hr

which is about 34 minutes 17 seconds

6 0
3 years ago
What kind of energy does a rubber band have when it is stretched?
RideAnS [48]
Elastic potential energy. When you stretch a rubber band it has the "potential" to do work, to fly in a given direction. In doing so it changes it's elastic potential energy to kinetic energy.
5 0
3 years ago
Read 2 more answers
A 1000 kg car moving a 10 m/s collides with a stationary 2000 kg truck. The two vehicles interlock as a result of the collision.
IgorLugansk [536]

Answer:

v₃ = 3.33 [m/s]

Explanation:

This problem can be easily solved using the principle of linear momentum conservation. Which tells us that momentum is preserved before and after the collision.

In this way, we can propose the following equation in which everything that happens before the collision will be located to the left of the equal sign and on the right the moment after the collision.

(m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}

where:

m₁ = mass of the car = 1000 [kg]

v₁ = velocity of the car = 10 [m/s]

m₂ = mass of the truck = 2000 [kg]

v₂ = velocity of the truck = 0 (stationary)

v₃ = velocity of the two vehicles after the collision [m/s].

Now replacing:

(1000*10)+(2000*0)=(1000+2000)*v_{3}\\v_{3}=3.33[m/s]

7 0
3 years ago
A 5.5kg radio is pushed across the table. If the acceleration is 5m/s to the right, find the net force exerted on the radio.
Sholpan [36]

Answer:

Net force exerted on the radio is 27.5 Newton.

Given:

Mass = 5.5 kg

Acceleration = 5 \frac{m}{s^{2} }

To find:

Force exerted on the radio = ?

Formula used:

F = ma

Where F = net force

m = mass

a = acceleration

Solution:

According to Newton's second law of motion,

F = ma

Where F = net force

m = mass

a = acceleration

F = 5.5 × 5

F = 27.5 Newton

Hence, Net force exerted on the radio is 27.5 Newton.


4 0
3 years ago
I need a quick way to answer a question on graphs in physics grade12
DIA [1.3K]
For you to answer a question on graphs, you have to first, identify the variables and coefficients given in the problem. Then, assess the Problem what is required given the <span>variables and coefficients. Lastly, develop a solution that would answer the required variables in the problem.</span>
6 0
3 years ago
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