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liubo4ka [24]
3 years ago
8

When a chemical reaction occurs in a sealed container, what is the total mass after the reaction compared to the total mass befo

re the reaction? A.
the same

B.
less

C.
more

D.
variable
Physics
2 answers:
Elis [28]3 years ago
5 0
A, When a chemical reaction occurs in a sealed container, the mass of the materials in the container stays the same. A chemical reaction is taking place in a sealed container.
oksano4ka [1.4K]3 years ago
4 0
The answer is A. the same.

Since the container is sealed, their will be no loss of material from the container which means that the mass won’t vary.
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A square plate of edge length 9.0 cm and negligible thickness has a total charge of 6.90 10-6 C. Estimate the magnitude E of the
SVETLANKA909090 [29]

Answer:

E= 4.35*10^6 N/C

Explanation:

Let's find the area charge density of the plate

α= 6.9*10^-6/9*10^-2 = 7.7*10^-5C/m2

Now we can calculate the electric field just of the plate

E =α/2e =7.7*10^-5/2*8.85*10^-12 = 4.35*10^6 N/C

7 0
3 years ago
While playing baseball with your friends your hands begin to sting after you ctach several fast balls.
muminat

Answer:

Explanation:

To stop a ball with high momentum in a small-time imparts a high amount of impact on hands. This is the reason for the stinging of hands.

The momentum of the ball is due to the mass and velocity. To prevent stinging in the hand one needs to lower his hands to increase the time of contact. In this way, the momentum transfer to the hands will be lesser.        

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3 years ago
7. These temperatures were recorded in Pasadena for a week in April. 87 85 80 78 83 86 90 Find each of these. (a) Mean (e) Range
slega [8]

Answer:

a) Mean = 84.14

b) Median = 85

c) Mode = no mode (since there is no variable that appears more than once in this dataset)

d) Midrange = 84

e) Range = 12

f) Variance = 14.69

g) Standard deviation = 3.83

Explanation:

The raw data to be processed is

87 85 80 78 83 86 90

a) Mean = (Σx)/N

The mean is the sum of variables divided by the number of variables

x = each variable

N = number of variables = 7

Mean = (87+85+80+78+83+86+90)/7

Mean = 84.14

b) Median is the number in the middle of the dataset when the variables are arranged in ascending or descending order.

Arranging the data in ascending order

78, 80, 83, 85, 86, 87, 90

The number in the middle is the 4th number = 85

Median = 85

c) Mode is the variable that occurs the most in a distribution.

For this question, all of the variables occur only once, with no variable occurring more than once. Hence, there is no mode for this dataset.

d) Midrange is the arithmetic mean of the highest and lowest number in the dataset.

Mathematically,

Midrange = (Highest + Lowest)/2

Midrange = (90 + 78)/2

Midrange = 84

e) Range is the difference the highest and the lowest numbers in a dataset.

Range = 90 - 78 = 12

f) Variance is an average of the squared deviations from the mean.

Mathematically,

Variance = [Σ(x - xbar)²/N]

xbar = mean

Σ(x - xbar)² = (78 - 84.14)² + (80 - 84.14)² + (83 - 84.14)² + (85 - 84.14)² + (86 - 84.14)² + (87 - 84.14)² + (90 - 84.14)² = 102.8572

Variance = (102.8572)/7

Variance = 14.69

g) Standard deviation = √(variance)

Standard deviation = √(14.69)

Standard deviation = 3.83

Hope this Helps!!!

8 0
3 years ago
Read 2 more answers
Calculate the wave number for the infrared absorption of D35Cl when there is a transition from v=0 to v=1 (Unit: cm^-1, 4-digit
AVprozaik [17]

Answer:

wave number = 0.3348 * 10⁻⁸ cm⁻¹

Explanation:

Given data:

K = 4.808 * 10^2 N/m

<u>Determine the wave number for the infrared absorption</u>

considering vibrational Spectre

k' =  2n / λ ---- ( 1 )

λ = c / v ----- ( 2 )

v = √k / u  --- ( 3 )

where : k' = wave number, λ = wavelength, c = velocity of light, v = frequency,  k = force constant, u = reduced mass

u = 1.90415 for  D35Cl

Input equations 2 and 3 into equation 1 to get the final equation

K' = 2n/c * √k / u

   = ( 2 * 3.14 ) / 2.98 * 10^8  ] * (√ 4.808 * 10^2 / 1.90415 )

   = 33.486 * 10⁻⁸ m⁻¹  ≈ 0.3348 * 10⁻⁸ cm⁻¹

6 0
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A Venn diagram shows the similarities and the differences of two things. In the area where the two circles overlap, the similari
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Answer:

found in the nucleus, has mass of one amu

Explanation:

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