That will depend on the units of the 3.0. We need to know if it's 3 feet, 3 yards, 3 meters, or 3 miles. Each one will have a different answer.
Because they occur at an atomic level, changing the actual structure of the thing.
Hope it helps
A uniform thin solid door has height 2.20 m, width .870 m, and mass 23.0 kg. Find its moment of inertia for rotation on its hinges. Is any piece of data unnecessary? So far, I don't understand how to calculate moments of inertia for things like this at all. I can do a system of particles, but when it comes to any ridgid objects, such as this door or rods or cylinders, I don't get it. So basically I have no idea where to even start with this.
so A
Answer:
Explanation:
Work done in carrying bricks
mgh
= 207 x 9.8 x 3.65
-= 7404.4 J
Work done in compressing gas
PΔV
Pressure x change in volume
1.8 x 10⁶ ΔV = 7404.4
ΔV = 7404.4 / 1.8 x 10⁶m³
= 4113.33 x 10⁻⁶ m³
= 4113.33 cc
