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algol [13]
3 years ago
15

Is 40/48 and 56/42 proportional

Mathematics
2 answers:
Lunna [17]3 years ago
3 0

No

The first fraction is under 1 whole while the second fraction is over 1 whole.

40/48 and 1  14/42 is what this is equal to.

May I have brainliest please? :)

prohojiy [21]3 years ago
3 0

Answer:

No

Step-by-step explanation:

the two fractions go down to

40/48= 5/6

56/42= 8/7

So, No

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LuckyWell [14K]

Answer: I'm guessing it would be a parabola, with the line going through -6 on the y-axis and passing through 2 and 6 on the x-axis, but we cannot see any answers, so therefore we can't answer it accurately.

Step-by-step explanation:

3 0
2 years ago
What is the distance between the house and the library?
MrMuchimi

Answer:

C (√34)

Step-by-step explanation:

Pythagoras' theorem states that: a² + b² = c², where c is the hypotenuse and what we are trying to figure out.

So, 3² + 5² = c²

9 + 25 = 34 = c²

c = √34

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5 0
2 years ago
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Find the zeros of polynomial x^2-3
Yakvenalex [24]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The required zeroes are ~

\boxed{ \boxed {\sqrt{3}} \:  \:  and  \:  \: \boxed{- \sqrt{3} }}

\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}

Let's equate the given polynomial with 0, to find its roots ~

that is ~

  • {x}^{2}  - 3 = 0

  • {x}^{2}  - ( \sqrt{3} ) {}^{2}  = 0

  • (x +  \sqrt{3} )(x -  \sqrt{3} ) = 0

there are two cases,

Case # 1 - when (x + √3) = 0

  • x +  \sqrt{3}  = 0

  • x =  -  \sqrt{3}

and

Case # 2 - when (x - √3) = 0

  • x -  \sqrt{3}  = 0

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4 0
2 years ago
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HELP ASAP WILL REWARD THIRTY POINTS.
OverLord2011 [107]
D.Annulus
is the correct answer....



HOPE IT HELPS YOU '_'
4 0
3 years ago
According to a recent survey of adults, approximately 62% carry cash on a regular basis. The adults were also
pochemuha

According to the probabilities given, it is found that the correct option regarding the independence of the events is given by:

No, P(carry cash) != P(carry cash|have children).

<h3>What is the probability of independent events?</h3>

If two events, A and B, are independent, we have that:

P(A \cap B) = P(A)P(B)

Which also means that:

P(A|B) = P(A)

P(B|A) = P(B)

In this problem, we have that:

  • 62% carry cash on a regular basis, hence P(cash) = 0.62.
  • 46% has children, hence P(children) = 0.46.
  • Of the 46% who have children, 85% carry cash on a regular basis, hence P(cash|children) = 0.85.

Since P(carry cash) != P(carry cash|have children), they are not independent.

More can be learned about the probability of independent events at brainly.com/question/25715148

6 0
2 years ago
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