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3 years ago

HELP!! 4 questions !!! easy points!! 25 points!! please answer quick!

Mathematics

1 answer:

Afina-wow [57]3 years ago

4 0

Step-by-step explanation:

(i) From the graph value of x varies -3 to 3 i.e.

$-3\leq x\leq 3$

and domain in the input values which function can take

So, option (d) is correct.

(ii) option (d) is correct as it represent the function $y=x$ . While all the other function does not satisfy the given conditions.

(iii) $(-14,-15), (-9,-10)$ are the parts of solution pair.

(iv) Option (c) and (d) represents the function as each element of the first set has a unique image in the second set.

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3. Find f[h(a+4)], given the functions below. *

mote1985 [20]

Answer:

C 5a^2 +70a +240

Step-by-step explanation:

We have given these following functions:

$f(x) = 5x, g(x) = -2x + 1, h(x) = x^2 + 6x + 8$

h(a+4)

This function is:

$h(a+4) = (a+4)^2 + 6(a + 4) + 8$

$h(a+4) = a^2 + 8a + 16 + 6a + 24 + 8$

$h(a+4) = a^2 + 14a + 48$

f[h(a+4)]

$f(x) = 5x$

Thus

$f(h(a+4)) = f(a^2+14a+48) = 5(a^2 + 14a + 48) = 5a^2 + 70a + 240$

The correct answer is given by option C.

8 0

3 years ago

Jaclyn started the week with $284.28 in her checking

Mashcka [7]

Answer:

$165.62

Step-by-step explanation:

284.28-40-48.39-30.27=165.62

5 0

3 years ago

Read 2 more answers

A grocery store gives away a $10 gift card to every 25th customer and a $20 gift card to every 60th customer. a. Which customer

steposvetlana [31]

To find the answer you need to find the common factor of numbers 25 and 60

25,50,75,100,125,150,175,200,225,250,275,300

60,120,180,240,300

The 300th customer will receive both cards, and a total of $220 and 17 gift cards were given away.

4 0

3 years ago

URGENT MATH HELP DUE BY 12:00 PM!

Sedaia [141]

I think D is the correct answer.

3 0

3 years ago

If p is a polynomial show that lim x→ap(x)=p(a

Lostsunrise [7]

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

Solution. Notice that

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

3 0

3 years ago