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taurus [48]
3 years ago
6

Magnesium metal burns with a bright white flame. What conclusions can you draw about the electron transitions that can take plac

e for a magnesium atom ?
Chemistry
1 answer:
labwork [276]3 years ago
4 0
They are activating which is causing them to do this
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A sample of carbon dioxide has a pressure of 1.2 atm, a volume of
GalinKa [24]

The answer for the following question is mentioned below.

<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>

Explanation:

Given:

Pressure of gas (P) = 1.2 atm

Volume of a gas (V) = 50.0 liters

Temperature (T) =650 K

To calculate:

no of moles present in the gas (n)

We know;

According to the ideal gas equation;

We know;

<u>P × V = n × R × T </u>

where,

P represents pressure of the gas

V represents volume of the gas

n represents no of the moles of a gas

R represents the universal gas constant  

where the value of R is 0.0821 L atm  mole^{-1}  K^-1

T represents the temperature of the gas

As we have to calculate the no of moles of the gas;

n = \frac{P*V}{R*T}

n = \frac{1.2*50.0}{0.0821*650}

n = \frac{60}{53.365}

n = 1.12 moles

<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>

3 0
3 years ago
Many repeating, simple subunits are joined together. What is the most likely
Hatshy [7]

Answer:

O a polymer

Explanation:

When many repeating simple subunits are joined together, this results into a polymer.

The simplest unit or smallest unit of any substance is called a monomer. When many units of a monomer joins together, a polymer results.

  • For proteins, the monomeric unit is amino-acid.
  • When they combine they form longer chain molecules called proteins.
  • For carbohydrates, the monomeric unit is called glucose.
  • When they are combined they give us a wide range of carbohydrate molecules.
6 0
3 years ago
When 3.00 g of sulfur are combined with 3.00 g of oxygen, 6.00 g of sulfur dioxide (SO2) are formed. What mass of oxygen would b
Drupady [299]
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

7 g S * 1 mol/32.06 g S = 0.218 mol S
Moles O₂ needed = 0.218 mol S * 3 mol O₂/2 mol S = 0.3275 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.3275 mol O₂ * 32 g/mol = 10.48 g O₂
3 0
3 years ago
In the sn2 experiment, what was the purpose of washing the distilled product with 5% naoh
photoshop1234 [79]

<span>The purpose of washing the product with NaOH is simply to neutralize any acid which remained or leaked after the 1st initial separation. The NaOH base reacts with the acid to form neutralization reaction products which are soluble in water.</span>

5 0
3 years ago
In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so
gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL

Putting values in above equation, we get:

1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0
3 years ago
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