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stira [4]
3 years ago
11

Match the chromatography term with its definition. The volume of solvent traveling through the column per unit time. The elapsed

time between sample injection and detection. The time required by a retained solute to travel through the column beyond the time required by the unretained solvent. The distance traveled by the solvent per unit time. Describes the amount of time that a sample spends in the stationary phase relative to the mobile phase. It is sometimes also called the capacity factor or capacity ratio. Volume of the mobile phase required to elute a solute from the column. Ratio of the adjusted retention times or retention factors of two solutes. It is sometimes also called the separation factor. The ratio of the solute concentrations in the mobile and stationary phases.
Chemistry
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

The statements are definitions to chromatography terms which have been highlighted below.

Explanation:

Match the chromatography term with its definition.

Volumetric Flow Rate = The volume of solvent traveling through the column per unit time.

Retention time = The elapsed time between sample injection and detection.

Adjusted Retention Time = The time required by a retained solute to travel through the column beyond the time required by the un -retained solvent.

Linear Flow Rate = The distance traveled by the solvent per unit time.

Retention factor = Describes the amount of time that a sample spends in the stationary phase relative to the mobile phase. It is sometimes also called the capacity factor or capacity ratio.

Relative Volume = Volume of the mobile phase required to elute a solute from the column.

Relative Retention = Ratio of the adjusted retention times or retention factors of two solutes. It is sometimes also called the separation factor.

Partition coefficient = The ratio of the solute concentrations in the mobile and stationary phases.

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Calculate the masses of oxygen and nitrogen that are dissolved in of aqueous solution in equilibrium with air at 25 °C and 760 T
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Explanation:

Let us assume that the volume of given aqueous solution is 7.5 L.

Therefore, according to Henry's law, the relation between concentration and pressure is as follows.

                C = \frac{P}{K_{h}}

where,   pressure (P) = 760 torr = 1 atm

According to Henry's law, constants for gases in water at 25^{o}C are as follows.

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   K_{h} for O_{2} = 7.9 \times 10^{2} bar/mol

    K_{h} for N_{2} = 1.6 \times 10^{3} bar /mol

Since, 21% oxygen is present in air so, its mass will be 0.21 g. Similarly, 78% nitrogen means the mass of nitrogen is 0.78 g.

Therefore, concebtrations will be calculated as follows.

      C(O_{2}) = \frac{0.21}{7.9 \times 10^{2}} = 2.66 \times 10^-4 mol/L  

      C(N_2) = \frac{0.78}{1.6 \times 10^3} = 4.875 \times 10^-4 mol/L

Now, we will calculate the number of moles as follows.

         n(O_{2}) = 7.5 \times 2.66 \times 10^-4 = 1.995 \times 10^-3 mol

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As the molar mass of O_2 = 32 g/mol

Hence, mass of oxygen will be as follows.

         Mass of O_2 = 32 \times 1.995 \times 10^-3 \times 1000

                           = 63.84 mg

As the molar mass of N_{2} = 28

       Mass of N_{2} = 28 \times 3.66 \times 10^-3 = 102.5 mg

Thus, we can conclude that mass of oxygen is 63.84 mg  and nitrogen is 102.5 mg.

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