The product will not be affected by the addition of twice as much Na₂CO₃.
<h3>What is Limiting reagent in stoichiometry ?</h3>
- The maximum quantity of the end product determined by a balanced chemical equation is known as the Stoichiometry.
- The limiting reactant is the one that is consumed first and sets a limit on the quantity of product(s) that can be produced, and the one which remains unconsumed after the final reaction is in Excess.
- Calculate the moles of each reactant present and contrast it with the mole ratio of the reactants in the balanced equation to determine which reactant is the limiting one.
Here,taking the stoichiometry into consideration, we find that the reaction happens with 1:1 ratio; so, adding twice the amount of Na₂CO₃ will lead to its excess making the other the limiting reactant, hence, it would not affect the yield of the product.
To know more about the Limiting reactant, refer to:
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1 μL = 10^-6 L by definition
So...
82 μL = 82x10^-6 L = 8.2x10^-5 L
Answer:
The answer to your question is
51.- 1.59 x 10⁻⁶
53.- NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl
Explanation:
51.- Convert 0.00159 ml to liters
Use a rule of three
1000 ml -------------- 1 l
0.00159 ml --------- x
x = (0.00159 x 1) / 1000
x = 0.00000159 l = 1.59 x 10⁻⁶ l
53.- Sodium hydrogen carbonate (NaHCO₃) reacts with hydrochloric acid to produce salt, water and carbon dioxide.
Sodium hydrogen carbonate = NaHCO₃
Hydrochloric acid = HCl
Reaction
NaHCO₃ + HCl ⇒ H₂O + CO₂ + NaCl
water = H₂O
carbon dioxide = CO₂
salt = NaCl
Robert Hooke was the scientist that coined the term cell
Answer:
Density = 11.4 g/cm³
Explanation:
Given data:
Density of lead = ?
Height of lead bar = 0.500 cm
Width of lead bar = 1.55 cm
Length of lead bar = 25.00 cm
Mass of lead bar = 220.9 g
Solution:
Density = mass/ volume
Volume of bar = length × width × height
Volume of bar = 25.00 cm × 1.55 cm × 0.500 cm
Volume of bar = 19.4 cm³
Density of bar:
Density = 220.9 g/ 19.4 cm³
Density = 11.4 g/cm³