All categories

3 years ago

Does liquid evaporate with adding heat or losing it

Chemistry

1 answer:

Marysya12 [62]3 years ago

6 0

Adding because evaporation speed is increased with increased temperature

You might be interested in

What do most psychologists believe to be the cause of development?

sattari [20]

b. interaction of nature and nurture

6 0

2 years ago

Read 2 more answers

This compound, an eight-carbon alkane, serves as the 100 octane standard for gasoline. It has five methyl groups, one quaternary

Reika [66]

Answer:

2,2,4-Trimethyl-pentane

Explanation:

Structural characteristics of the compound is as follows:

Has five methyl group
Has one quaternary carbon
No. double bond
Gives four monochloro substitution products

Compound must have straight chain of 5 carbons.

Three methyl substituents are attached to 2 and 4 carbons.

Therefore, IUPAC name of the compound will be 2,2,4-Trimethyl-pentane.

5 0

2 years ago

Which of these solutes raises the boiling point of water the most?

sergey [27]

Answer:

D. ionic sodium phosphate (Na3PO4)

Explanation:

Molecule for molecule, the solute that raises the boiling point of water the most is the one that makes the most particles in the solution. Lithium chloride breaks up into two ions (Li+ and Cl-). So does sodium chloride (Na+ and Cl-). Molecular molecules don't break up at all, so sucrose has only 1 particle per molecule. Sodium phosphate makes 4 total particles (3 Na+ ions and 1 PO4^3-). And magnesium bromide would make 3 particles (1 Mg2+ and 2 Br-). So the most is 4.

6 0

3 years ago

Help asap. How many moles are 5.55x10^25 atoms of Mg

LekaFEV [45]

Answer:

$\boxed {\boxed {\sf About \ 92.2 \ moles \ of \ Magnesium}}$

Explanation:

To convert from atoms to moles, we must Avogadro's number:

6.022*10²³

This number tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, it is atoms of magnesium in 1 mole.

6.022 *10²³ atoms Mg / 1 mol mg

Now, let's set up an expression using:

$\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}$

Multiply this by the given number of atoms.

$5.55*10^{25} \ atoms \ Mg *\frac {6.022 * 10^ {23} \ atoms \ Mg}{ 1 \ mol \ Mg}$

Flip the fraction so the atoms of magnesium can cancel.

$5.55*10^{25} \ atoms \ Mg *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23} \ atoms \ Mg}$

$5.55*10^{25} *\frac { 1 \ mol \ Mg }{6.022 * 10^ {23}}$

Multiply and condense this into 1 fraction.

$\frac { 5.55*10^{25} \ mol \ Mg }{6.022 * 10^ {23}}$

$92.1620724 \ mol \ Mg$

The original measurement had 3 significant figures, so our answer must have that many as well. For the number we calculated, that is the tenth place. The 6 in the hundredth place tells us to round the 1 to a 2.

$92.2 \ mol \ Mg$

It is about 92.2 moles of magnesium.

3 0

3 years ago

Balancing equations

eduard

For fine have to usual

5 0

2 years ago