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Dominik [7]
3 years ago
7

Which equation represents a double replacement reaction

Chemistry
2 answers:
jek_recluse [69]3 years ago
7 0
LiOH+HCL LiCL+H2O represents a double replacement reaction.
ryzh [129]3 years ago
5 0

Options

(1) 2Na + 2H2O → 2NaOH + H2

(2) CaCO3 → CaO + CO2

(3) LiOH + HCl → LiCl + H2O

(4) CH4 + 2O2 → CO2 + 2H2O

Answer:

(3) LiOH + HCl → LiCl + H2O

Explanation:

A double displacement reaction, also known as a double replacement reaction or metathesis, is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

A typical example is given as;

AB + CD --> BC + AD

The only reaction that matched the axample given in the options is that of option C,

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1. Show that heat flows spontaneously from high temperature to low temperature in any isolated system (hint: use entropy change
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Answer:

1 ) Δs ( entropy change for hot block ) = - Q / th  ( -ve shows heat lost to cold block )

Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

2) ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

Explanation:

<u>1) To show that heat flows spontaneously from high temperature to low temperature </u>

example :

Pick two(2) solid metal blocks with varying temperatures ( i.e. one solid block is hot and the other solid block is cold )

Place both blocks for time (t ) in an insulated system to reduce heat loss or gain to or from the environment

Check the temperature of both blocks after time ( t ) it will be observed that both blocks will have same temperature after time t ( first law of thermodynamics )

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Δs ( entropy change for cold block ) = Q / tc

∴ Total Δs = ΔSc + ΔSh

                 = Q/tc - Q/th

<u>2) Entropy change for Decomposition of mercuric oxide </u>

2HgO (s) → 2Hg(l) + O₂ (g)

Δs = positive

there is transition from solid to liquid and the melting point of mercury ( the point at which reaction will take place ) = 500⁰C

hence ΔSdecomposition = S⁻ Hg  -  S⁻ HgO =

Δh of reaction = 181.6 KJ

Temp = 500 + 273 = 773 k

hence ΔSdecomposition = Δh / Temp = ( 181.6 * 10^3 / 773 ) = 234.928 J/k

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Explanation:

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