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Dominik [7]
3 years ago
7

Which equation represents a double replacement reaction

Chemistry
2 answers:
jek_recluse [69]3 years ago
7 0
LiOH+HCL LiCL+H2O represents a double replacement reaction.
ryzh [129]3 years ago
5 0

Options

(1) 2Na + 2H2O → 2NaOH + H2

(2) CaCO3 → CaO + CO2

(3) LiOH + HCl → LiCl + H2O

(4) CH4 + 2O2 → CO2 + 2H2O

Answer:

(3) LiOH + HCl → LiCl + H2O

Explanation:

A double displacement reaction, also known as a double replacement reaction or metathesis, is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.

A typical example is given as;

AB + CD --> BC + AD

The only reaction that matched the axample given in the options is that of option C,

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The correct Answer for this question is D
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A baseball a football and a bowling ball are thrown with the same force
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Answer:

the bowling ball will move fastest

Explanation:

because it is heaviest

7 0
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What would be the Name of a Chemical made of 14 g Lithium, 32 g Sulfur, and 64 g Oxygen?
bulgar [2K]

The name of the chemical made of 14 g Lithium or 2 moles Lithium, 32 g Sulfur or 1 mol sulfur and 64 g oxygen or 4 moles of oxygen is Lithium sulfate. From the chemical reation:

<span>2Li + S + 4O > Li2SO4</span>
7 0
3 years ago
Given that the molar mass of NaCl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of
Stells [14]

<u>Given information:</u>

Mass of NaCl (m) = 87.75 g

Volume of solution (V) = 500 ml = 0.5 L

Molar mass of NaCl (M) = 58.44 g/mol

<u>To determine:</u>

The molarity of NaCl solution

<u>Explanation:</u>

Molarity is defined as the number of moles of solute(n) dissolved per liter of solution (V)

i.e. M = moles of solute/liters of solution = n/V

Moles of solute (n) = mass of solute (m)/molar mass (M)

moles of NaCl = 87.75 g/58.55 g.mol-1 = 1.499 moles

Therefore,

Molarity of NaCl = 1.499 moles/0.5 L = 2.998 moles/lit ≅ 3 M

<u>Ans: (D)</u>

4 0
3 years ago
Read 2 more answers
The maximum amount of nickel(II) cyanide that will dissolve in a 0.220 M nickel(II) nitrate solution is...?
sweet [91]

Answer : The maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

Explanation :

The solubility equilibrium reaction will be:

                       Ni(CN)_2\rightleftharpoons Ni^{2+}+2CN^-

Initial conc.                        0.220       0

At eqm.                             (0.220+s)   2s

The expression for solubility constant for this reaction will be,

K_{sp}=[Ni^{2+}][CN^-]^2

Now put all the given values in this expression, we get:

3.0\times 10^{-23}=(0.220+s)\times (2s)^2

s=5.84\times 10^{-12}M

Therefore, the maximum amount of nickel(II) cyanide is 5.84\times 10^{-12}M

7 0
2 years ago
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