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Free_Kalibri [48]
3 years ago
14

60 points one of the questions im stuck on

Chemistry
2 answers:
Dafna1 [17]3 years ago
7 0

Answer:

6 meters per second

Explanation:

they fly 60 meters in 10 seconds. So to find how many meters they fly in one second, we divide by 10.

60m/10secs = 6 m/s

Yuri [45]3 years ago
4 0

Answer:

6 m/s is the answer.

Explanation:

speed = distance/time

(please mark me brainliest if you can)

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Photosynthesis is the process where plants create energy. It requires water, carbon dioxide and sunlight. The end result is glucose, which the plants consume, and oxygen. Cellular respiration requires oxygen and glucose. The end result is carbon dioxide, ATP, and water.

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How many moles are in 1.20 x 10^21 atoms of Phosphorus?
Ludmilka [50]

Answer:

You would get 19.969 moles

Explanation:

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Is Squeezing oranges to make orange juice a chemical or physical change?
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Read 2 more answers
A roller coaster is accelerating at 10m/s² before it comes to an abrupt stop at the end of the ride. The mass of the roller coas
alexgriva [62]

Answer:

<h2>9000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 900 × 10

We have the final answer as

<h3>9000 N</h3>

Hope this helps you

8 0
3 years ago
Iridium has two naturally occurring isotopes, Iridium-191 and Iridium-193. If the average atomic mass of orodum s 192.217, what
Lina20 [59]

Answer:

The percent isotopic abundance of Ir-193 is 60.85 %

The percent isotopic abundance of Ir-191 is 39.15 %

Explanation:

we know there are two naturally occurring isotopes of iridium, Ir-191 and Ir-193

First of all we will set the fraction for both isotopes

X for the isotopes having mass 193

1-x for isotopes having mass 191

The average atomic mass is 192.217

we will use the following equation,

193x + 191(1-x) = 192.217

193x + 191 - 191x = 192.217

193x- 191x = 192.217 - 191

2x = 1.217

x= 1.217/2

x= 0.6085

0.6085 × 100 = 60.85 %

60.85% is abundance of Ir-193 because we solve the fraction x.

now we will calculate the abundance of Ir-191.

(1-x)

1-0.6085 =0.3915

0.3915× 100= 39.15 %

6 0
3 years ago
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