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iogann1982 [59]
3 years ago
14

Water is a polar molecule, meaning the electrons that are shared between the atoms aren't shared equally so oxygen attracts more

electrons than hydrogen. What analogy best compares this?
Chemistry
1 answer:
amm18123 years ago
4 0

Answer:

Magnet with a positive and a negative pole

Explanation:

A great analogy to demonstrate what a polar molecule looks like is to imagine a magnet. A magnet has one positively charged end and one negatively charged end, two poles, that is.

Imagine that we have a magnet of a shape of a prism (water molecule has a bent shape). The two base vertices of the face of the triangle are positively charged, that's because hydrogen is less electronegative than oxygen and, hence, the two hydrogen atoms are partially positively charged in a water molecule.

Oxygen is more electronegative than hydrogen meaning it has a greater electron-withdrawing force, so electrons are closer to oxygen within the O-H bonds. Oxygen, as a result, becomes partially negatively charged, so it's our negative pole of the magnet.

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What are the roles of producers, primary consumers, secondary consumers, tertiary consumers for the trophic levels in the energy
Nesterboy [21]
     This question is more for Biology than Chemistry, but the role of producers is to make energy (food) to be consumed. In a pyramid diagram, the producers would be at the bottom. Now going up the pyramid, the primary conumers are the first to consume producers and obtain energy from them. As you go up the pyramid, the secondary consumers will consume the primary consumers as a way to obtain energy, and the same goes for tertiary consumers towards secondaries.

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I hope this answers your question. 
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Balance this equation. if a coefficient of "1" is required, choose "blank" for that box.
blondinia [14]
Step 1: Write Imbalance Equation

                            CH₃CHO  +  O₂    →    CO₂  +  H₂O

Step 2: Balance Carbon Atoms:
                                                 There are 2 carbon atoms at reactant side and one at product side. So multiply CO₂ with 2 to balance them. i.e.

                             CH₃CHO  +  O₂    →    2 CO₂  +  H₂O 

Step 3: Balance Hydrogen Atoms:
                                                      There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.

                    CH₃CHO  +  O₂    →    2 CO₂  +  2 H₂O

Step 4: Balance Oxygen Atoms:
                                                   There are 3 Oxygen atoms at reactant side and 6 Oxygen atoms at product side. In order to balance them multiply O₂ on reactant side by 2.5 (5/2). i.e  

                    CH₃CHO  +  5/2 O₂    →    2 CO₂  +  2 H₂O

Step 6: Eliminate Fraction:
                                         Multiply overall equation by 2 to eliminate fraction. i.e. 

                    2 CH₃CHO  +  5 O₂    →    4 CO₂  +  4 H₂O
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