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3 years ago

I’d appreciate it please helpppp

Mathematics

2 answers:

xxTIMURxx [149]3 years ago

4 0

Answer:

The answer is B. a proportional graph is a straight line that always goes through the origin 0, 0

Alexandra [31]3 years ago

4 0

Answer:

The answer is B

Step-by-step explanation:

The line is straight and it passes through the origin (0,0)

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Estimate the cost of painting a concrete patio if it is a 12 foot by 12 foot rectangle, and a quart of paint that covers 47 squa

umka21 [38]

Answer: $36.68 or $35.97. Read below.

Step-by-step explanation: You need to multiply the 12 foot by 12 foot and you would get 144 sq feet. Then divide 47 into 144. You will be left with 3.06, and if you need to round, you can round that to 3. Then you need to multiply 3 by $11.99 and you will be left with the cost for the paint, which is $35.97 if you do round to a three, and $36.68 if you do not round the three. So your answer is either $36.68 or $35.97 depending on whether you round or not.

6 0

2 years ago

Find the value(s) of k such that 4x² + kx + 4 = 0 has 1 rational solution

Blababa [14]

Answer:

If you mean only one rational solution, the answer is

$k_1 = 8, k_2 = -8$

If you mean at least 1 rational solution, the answer is

$k\in (-\infty, -8]\cup[8, \infty)$

Step-by-step explanation:

$4x^2 + kx + 4 = 0$

Let's calculate the discriminant.

$\Delta = b^2 - 4ac$

$\Delta = k^2 -4 \cdot 4 \cdot 4$

$\Delta = k^2 -64$

Now, remember that:

$\text{If } \Delta > 0 : \text{2 Real solutions}$

$\text{If } \Delta = 0 : \text{1 Real solution}$

$\text{If } \Delta < 0 : \text{No Real solution}$

Therefore, I will just consider the first two cases.

$k^2 - 64 > 0$

and

$k^2 -64 = 0$

$\boxed{\text{For } k^2 - 64 > 0}$

$k^2 > 64 \Longleftrightarrow k>\pm\sqrt{64} \Longleftrightarrow k\in (-\infty, -8)\cup(8, \infty)$

$\boxed{\text{For } k^2 - 64 = 0}$

$k^2 = 64 \Longleftrightarrow k=\pm\sqrt{64} \implies k_1 = 8, k_2 = -8$

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%5Cfbox%5Cpurple%7BQuestion%7D" id="TexFormula1" title="\huge\fbox\purple{Question}" al

zubka84 [21]

The HCF are

This is the common factor that is the highest that a group of numbers can have in common.

1. 6 and 15

factors of 6 = 1, 2, 3, 6

factors of 15: 1, 3, 5, 15

The HCF is the number they have in common = 3

2. 12 and 18

The factors of 12: 1, 2, 3, 4, 6, 12

The factors of 18: 1, 2, 3, 6, 9, 18

The HCF = 6

3. 15 and 24

Factors of 15: 1, 3, 5, 15

Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The HCF = 3

4. 24 and 36

The factors of 24: 1, 2, 3, 4, 6, 8, 12, 24

The factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

The HCF : 12

5. 30 and 48

The factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

The factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The HCF = 6

6. 36 and 54

The factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 54: 1, 2, 3, 6, 9, 18, 27, 54

The hcf = 18

7. 32,40 and 56

The factors of 32: 1, 2, 4, 8, 16, 32

The factors of 40: 1, 2, 4, 5, 8, 10, 20, 40

The factors of 56: 1, 2, 4, 7, 8, 14, 28, 56

The HCF is 8

8. 28,42 and 70

The factors of 28: 1, 2, 4, 7, 14, 28

The factors of 42: 1, 2, 3, 6, 7, 14, 21, 42

The factors of 70: 1, 2, 5, 7, 10, 14, 35, 70

The HCF = 14

9. 30,75 and 90

The factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

The factors of 75: 1, 3, 5, 15, 25, 75

The factors of 90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The HCF is 15

Read more on HCF here;

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8 0

2 years ago

Can someone please help me with question 9

nataly862011 [7]

There are 24 oranges and 36 apples.

Each basket has to have the same number of fruit

So lets say that each basket will have exactly one orange and apple.

To get the maximum number of baskets, we have to use either all of the apples or all of the oranges.

You can't have 36 baskets, because you only have 24 oranges, even though there are enough apples.

But you can 24 baskets, because there are enough apples and oranges.

So you can use all of the oranges to make 24 baskets (and you'll be left with 12 apples)

Answer: F. 24.

4 0

3 years ago

On the same two days, the Belly Company's Stock also began at $36. However, by the end of the first day, the stock had dropped b

sineoko [7]

It's still 36% because you droppet it and then gain it back up

8 0

3 years ago