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olchik [2.2K]
3 years ago
12

PLEASE HELP show the calculation of the number of neutrons of hydrogen​

Physics
1 answer:
xz_007 [3.2K]3 years ago
7 0
The answer is 2.3 hope this helps texted me and tell me if it’s right
You might be interested in
What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 43
kiruha [24]

Answer:

The magnification is m  = 0.3674

Explanation:

From the question we are told that

  The  power of the lens is  P = -4.00 D(dioptre)

Generally  1 dioptre = 1 \ meter

  The object distance is u =  -43 \ cm the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )

 Generally the focal length is mathematically represented as

          f = \frac{1}{P}  

   =>f = \frac{1}{4.00 }  

  =>  f = 0.25 \ m

converting to  cm  

 =>   f = 0.25 \ m = 0.25 * 100 = 25 \ cm

Generally from lens equation  we have that  

     \frac{1}{f} +\frac{1}{v} -\frac{1}{u}

=>  \frac{1}{25} +\frac{1}{v} -\frac{1}{-43}

=>   v =  -15.8 \ cm

Generally the magnification is mathematically represented as

      m  = \frac{v}{u}

=>    m  = \frac{- 15.8}{-43}

=>    m  = 0.3674

6 0
3 years ago
Give a real-world example of how energy is transformed from electrical energy to thermal energy. Describe how the heat can be tr
timofeeve [1]

Answer:

A microwave

Explanation:

Car

Lightbulb is a really good one

Same with the sun. That one has Chemical as well

3 0
2 years ago
The Earth's Radius is 6.3710x106 m and mass is 5.9742x1024 kg. What is the acceleration due to gravity at Mount Everest (elevati
Shalnov [3]

Answer is

9.773m/s^2

-----------------------------------------------------------------------------

Given,

h=8848m

The value of sea level is 9.08m/s^2. So, Let g′ be the acceleration due to the gravity on Mount Everest.

g′=g(1 − 2h/h)

=9.8(1 - 6400000/17696)

=9.8(1 − 0.00276)

9.8×0.99724

=9.773m/s^2

Thus, the acceleration due to gravity on the top of Mount Everest is =9.773m/s^2

-----------------------------------------------------------------------

hope this helps :)

3 0
3 years ago
2. An athlete of average size is hanging from the end of a 20 m long rope, which has a mass of 4 kg and is attached to a hook in
a_sh-v [17]

Answer:

  t = 0.319 s

Explanation:

With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by

             v = √T/λ

Linear density is

           λ = m / L

           λ = 4/20

           λ = 0.2 kg / m

The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg

           T = W = mg

           T = 80 9.8

           T = 784 N

The pulse rate is

          v = √(784 / 0.2)

          v = 62.6 m / s

The time it takes to reach the hook can be searched with kinematics

          v = x / t

          t = x / v

          t = 20 / 62.6

          t = 0.319 s

7 0
3 years ago
What is the significance of Nucleotides in Chromosomes?​
fgiga [73]

Answer:

it comprises of the DNA/RNA bipolymer molecules

3 0
3 years ago
Read 2 more answers
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