I just solved similar type of question. You can refer to my solution which I have attached
Potential energy U = mgh
Given h = 123 m,
mg = F = 780 N
Then
U = (123)(780)
= 95940
= 9.59 x 10^4
Answer:
d = 6.43 cm
Explanation:
Given:
- Speed resistance coefficient in silicon n = 3.50
- Memory takes processing time t_p = 0.50 ns
- Information is to be obtained within T = 2.0 ns
Find:
- What is the maximum distance the memory unit can be from the central processing unit?
Solution:
- The amount of time taken for information pulse to travel to memory unit:
t_m = T - t_p
t_m = 2.0 - 0.5 = 1.5 ns
- We will use a basic relationship for distance traveled with respect to speed of light and time:
d = V*t_m
- Where speed of light in silicon medium is given by:
V = c / n
- Hence, d = c*t_m / n
-Evaluate: d = 3*10^8*1.5*10^-9 / 3.50
d = 0.129 m 12.9 cm
- The above is the distance for pulse going to and fro the memory and central unit. So the distance between the two is actually d / 2 = 6.43 cm
This is called a<em> standing wave</em> since the waves don't move ALONG the rope. They just kind of stand in one place on the rope. if you just whip a long rope that's not tied to anything, you see the wave move along the rope, this is a TRANSVERSE wave. When you crack a qhip you send a transverse wave down the whip which concentrates in the tip, accelerating the tip to faster than the speed of sound resulting in a tiny sonic boom or "whip crack".
The time of flight of the launched particle will be 2v₀ sinθ / g.
<h3>What is kinematics?</h3>
The study of motion without considering the mass and the cause of the motion.
A projectile is launched from level ground with an initial speed v₀ at an angle θ with the horizontal. If air resistance is negligible.
Then the time of flight of the launched particle will be given as,
Determine how long it requires the projectile to reach its highest point in order to calculate the flight duration. Just twice as long as the maximum altitude is the travel time.
At maximum height, 
.
The time to reach maximum height is given as
The time of flight is given as,
Substituting in 
, then we have
The time of flight of the launched particle will be 2v₀ sinθ / g.
More about the kinematics link is given below.
brainly.com/question/7590442
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