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2 years ago

If a light transmitts threw a material does the material absorb it?

1 answer:

3 0

When a light wave with a single frequency strikes an object, a number of things could happen. The light wave could be absorbed by the object, in which case its energy is converted to heat. The light wave could be reflected by the object. And the light wave could be transmitted by the object.

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Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation dist

steposvetlana [31]

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge $q = -6.25 \times 10^{-6}$ C

Separation between two charges $r = 0.02$ m

For finding the electrical force,

According to the coulomb's law

$F = \frac{k q^{2} }{r^{2} }$

Here, force between two balloons are repulsive because both charges are same.

Where $k = 9 \times 10^{9}$

$F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2} }{4 \times 10^{-4} }$

$F = 878.9$ N

Therefore, the electric force between them is 878.9 N

8 0

3 years ago

How can x-rays make pictures of the inside of solid objects

Mariana [72]

X-rays have high energy and can penetrate matter that light cannot.

6 0

3 years ago

Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame

VashaNatasha [74]

Answer:

$V = 5.30 *10^{-2} \ m^3$

$v_1 = 0.3127 \ m/s$

Explanation:

From the question we are told that

The number of identical drippers is n = 60

The diameter of each hole in each dripper is $d = 1.0 \ mm = 0.001 \ m$

The diameter of the main pipe is $d_m = 2.5 \ cm = 0.025 \ m$

The speed at which the water is flowing is $v = 3.00 \ cm/s = 0.03 \ m/s$

Generally the amount of water used in one hour = 3600 seconds is mathematically represented as

$V = A * v * 3600$

Here A is the area of the main pipe with value

$A = \pi * \frac{d^2}{4}$

=> $A = 3.142 * \frac{0.025^2}{4}$

=> $A = 0.0004909 \ m^2$

=> $V = 0.0004909 * 0.03 * 3600$

=> $V = 5.30 *10^{-2} \ m^3$

Generally the area of the drippers is mathematically represented as

$A_1= n * \pi \frac{d^2}{4}$

=> $A_1 = 60 * 3.142 * \frac{0.001 ^2}{4}$

=> $A_1 = 4.713 *10^{-5} \ m^2$

Generally from continuity equation we have that

$Av = A_1 v_1$

=> $0.0004909 * 0.03 = 4.713 *10^{-5} * v_1$

=> $v_1 = 0.3127 \ m/s$

3 0

3 years ago

How long did it take beagle to sail from Tahiti back to Falmouth, England?

Radda [10]

Answer:

On 2 October 1836, the Beagle entered the English port of Falmouth after a voyage which had lasted for four years, nine months and five days.

5 0

3 years ago

A grinding wheel is a uniform cylinder with a radius of 8.5cm and a mass of 0.580kg. Calculate

Kaylis [27]

Answer:

(a) its moment of inertia about its center is 0.002095 kgm²

(b) Applied torque is 0.071813 Nm

Explanation:

Given;

Radius of the grinding wheel, R = 8.5cm

Mass of the grinding wheel, m = 0.580kg

Part (a) its moment of inertia about its center

I = ¹/₂MR²

I = ¹/₂(0.58)(0.085)²

I = 0.002095 kgm²

Part (b)

Given;

initial angular velocity, ωi = 1500rpm = 157.1 rad/s

final angular velocity, ωf = 1500rpm = 157.1 rad/s

Initial torque, τi = I x αi

αi = ωi / t

αi = 157.1 / 5 = 31.42 rad/s²

τi = 0.002095 x 31.42

τi = 0.06583 Nm

Final torque, τf = I x αf

αf = ωf / t

αf = 157.1 / 55 = 2.856 rad/s²

τf = 0.002095 x 2.856

τf = 0.005983 Nm

Applied torque = τi + τf

= 0.06583 Nm + 0.005983 Nm

= 0.071813 Nm

8 0

3 years ago

If a light transmitts threw a material does the material absorb it?​

If a light transmitts threw a material does the material absorb it?