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nikitadnepr [17]
3 years ago
7

When determining molecular polarity, which scenario is not possible:

Chemistry
2 answers:
Fynjy0 [20]3 years ago
6 0

Answer: Option C is correct

A polar molecule with nonpolar bonds

Explanation:

A polar molecule with nonpolar bonds cannot be polar because a polar molecule has net dipole that it has one end slightly positive and the other end slightly negative which allows the distribution of atoms .

Therefore it cannot have non polar bonds because non polar bonds allow electrons to be shared equally and it take place between non elemental substances or substances that are not elements , it cannot occur in elemental substances because these substances have different electronegativities which can be held by polar bonds alone.

defon3 years ago
3 0

Answer:

The correct answer is <em>C. A polar molecule with nonpolar bonds</em>

Explanation:

Polarity is the property of a molecule of having a dipole moment. Based on this, a molecule can be polar -with dipole moment- o nonpolar. The polarity of a molecule is determined by:

- the presence of elements with differences in electronegativity which results in <em>polar bonds.</em>

- geometry of the molecule

Polar bonds are vectors and if they are opposite (equal in magnitude with opposite direction) so they are cancelled out. A polar molecule must have polar bonds, buy they can be cancelled out by opposite positions in the molecule geometry. For example, CO₂ (carbon dioxide) has polar bonds C-O because they are composed by elements with different electronegativities, but the molecule is linear so the two bonds C-O are cancelled out and the molecule is nonpolar.

Therefore, from the options, the only non possible scenario is C - a polar molecule with nonpolar bonds - because polar molecules always have polar bonds. The opposite situation can be true: a non polar molecule wiith polar bonds as we saw in the example of CO₂.

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Answer:

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Explanation:

Hello,

In this case, one could represent the given reaction as:

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Since it is endothermic. Thus, solving the (a) statement, one identifies the heat as a reagent, that is why the reaction cools down as it progress, therefore, by increasing the temperature, heat is added, that is, a reagent is added, which shifts the equilibrium rightwards, in other words, more NO is produced so its concentration increases.

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\Delta \nu =2-1-1=0

Such value implies that the pressure has no effect on the concentration, taking into account the following form of the law of mass action:

Kp=Kc(RT)^{\Delta \nu }

Thus, since \Delta \nu =0, Kp=Kc, so no effect in concentration is due to the pressure.

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6 0
3 years ago
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