Answer:

Step-by-step explanation:
What is the cube root of
? This is the question.
We can write:
![\sqrt[3]{27a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D)
We will use the below property to simplify:
![\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%2Ab%7D%3D%5Csqrt%5Bn%5D%7Ba%7D%20%20%5Csqrt%5Bn%5D%7Bb%7D)
So, we have:
![\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27a%5E%7B12%7D%7D%20%3D%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D)
We will now use below property to further simplify:
![\sqrt[n]{x} =x^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%20%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Thus, we have:
![\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%20%5Csqrt%5B3%5D%7Ba%5E%7B12%7D%7D%20%3D3%2A%28a%5E%7B12%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
We know power to the power rule: 
Now, we have:

This is the correct answer: 
divides
if the remainder is
. (This is the remainder theorem)
Then we must have

Answer:
-3(4x+3)+5x (Given) 1/2 (6k+10)+5k (given)
-12x-9+5x (distribution) 3k+5+5k (distribution)
-12x+5x-9 (associative) 3k+5k+5 (associative)
-7x-9 (Combine like terms) 8k+5 (combine like terms)
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
what ever the number is, it has to be on THAT number. The alligator thing think of it as a arrow it points to the direction, follow the arrow