The list of equations is shown in the picture which equation has No Solution, One Solution, and Infinitely Many Solutions.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have given a linear equation in one variable.
![\rm \dfrac{1}{2}y + 3.2y = 20](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B1%7D%7B2%7Dy%20%2B%203.2y%20%3D%2020)
After solving:
y = 5.40 (one solution)
![\rm \dfrac{15}{2}+ 2z -\dfrac{1}{4}=4z+\dfrac{29}{4} -2z](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B15%7D%7B2%7D%2B%202z%20-%5Cdfrac%7B1%7D%7B4%7D%3D4z%2B%5Cdfrac%7B29%7D%7B4%7D%20%20-2z)
After solving:
![\rm \dfrac{15}{2} -\dfrac{1}{4}=\dfrac{29}{4}](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B15%7D%7B2%7D%20-%5Cdfrac%7B1%7D%7B4%7D%3D%5Cdfrac%7B29%7D%7B4%7D)
(Infinitely Many Solutions)
3z + 2.5 = 3.2 + 3z
2.5 = 3.2 (no solution)
Similarly, we can identify which equation has No Solution, One Solution, and Infinitely Many Solutions.
Thus, the list of equations is shown in the picture which equation has No Solution, One Solution, and Infinitely Many Solutions.
Learn more about the linear equation here:
brainly.com/question/11897796
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Answer:
There are 6 adults. <em>My mistake! I had the wrong equation. 3 + 9a = 57.</em>
Step-by-step explanation:
- <u>There is only 1 child in the group.</u>
- Cost for children is 3$.
- <u>The cost for adults is 9$.</u>
- 9 * 6 = 54
- 3 * 1 = 3
- 3 + 9a = 57
- Simplify:
- 6 Adults.
248/4 = 62
to check if you are right
you do
62*4= 248
or you can do
248/62= 4
You can check in both way
Answer:
![1680](https://tex.z-dn.net/?f=1680)
Step-by-step explanation:
we need a 4-digit number from the numbers
(without repetition ).
possible number at thousand place ![=8](https://tex.z-dn.net/?f=%3D8)
Possible numbers at hundred place![=8-1=7](https://tex.z-dn.net/?f=%3D8-1%3D7)
Possible numbers at
place ![=7-1=6](https://tex.z-dn.net/?f=%3D7-1%3D6)
possible number at unit place ![=6-1=5](https://tex.z-dn.net/?f=%3D6-1%3D5)
<em>So total possible numbers</em>
![=8\times7\times6\times5\\=1680](https://tex.z-dn.net/?f=%3D8%5Ctimes7%5Ctimes6%5Ctimes5%5C%5C%3D1680)
<u>Other method :</u>
We are taking
numbers out of
and here order matters so we will use permutation.
Total possible numbers ![=^8P_{4}](https://tex.z-dn.net/?f=%3D%5E8P_%7B4%7D)
![\frac{8!}{(8-4)!}\\ =\frac{8!}{4!}\\ =8\times7\times6\times5\\=1680](https://tex.z-dn.net/?f=%5Cfrac%7B8%21%7D%7B%288-4%29%21%7D%5C%5C%20%3D%5Cfrac%7B8%21%7D%7B4%21%7D%5C%5C%20%3D8%5Ctimes7%5Ctimes6%5Ctimes5%5C%5C%3D1680)