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2 years ago

Find the slope given the points (-5,-3) and (2,4)

Mathematics

2 answers:

Setler79 [48]2 years ago

8 0

Answer:

The slope of the line is 1.

Step-by-step explanation:

We are given two coordinate points:

(-5, -3)
(2, 4)

We can use the rate of change formula to find the slope of the points.

$\displaystyle \frac{\triangle y}{\triangle x}$

In mathematics, coordinate pairs are labeled as:

$(x_1, y_1) \ \text{and} \ (x_2, y_2)$

Therefore, we can relabel our points:

$x_1 = -5$
$y_1 = -3$
$x_2 = 2$
$y_2 = 4$

After we do this, we can expand the rate of change formula:

$\displaystyle m = \frac{y_2-y_1}{x_2-x_1}$

Now, we can use simple substitution to solve for m, or the slope.

$\displaystyle m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{4-(-3)}{2-(-5)}\\\\m = \frac{7}{7}\\\\m = 1$

Therefore, the slope of the line is 1.

grin007 [14]2 years ago

6 0

Answer:

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

= (4 - -3)/(2 - -5)

= ( 4+3)/( 2+5)

= 7/7

= 1

You might be interested in

find the measure of each angle acute angle in a right triangle where the measure of one acute angle is twice the difference of t

Marina86 [1]

Answer:

The measures of the acute angles are 38 and 52 degrees.

Step-by-step explanation:

In a right triangle, there are three angles, a right angle and two acute angles. In every traingle, the sum of the measures of the angles is 180 degrees. Let's call the acute angles $a$ and $b$ .

$a + b +90 = 180$

The problem also says that one angle is twice the difference of the other angle and 12. That would look like this:

$a = 2(b-12)$

Now we have two equations. If we simplify them, we get these:

$\left \{ {{a=90-b} \atop {a=2b-24}} \right.$

Now you can substitute $a$ in the first equation for $a$ in the second equation

$90-b=2b-24$

Add $b$ to both sides of the equation

$90 = 3b-24$

Add $24$ to both sides

$114 = 3b$

Divide both sides by 3

$38 = b$

Now, you can substitute $38$ for $b$ in the first equation and simplify.

$a = 90-38$

$a=52$

Therefore,

$a=52$ , and $b=38$

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3 0

2 years ago

Read 2 more answers

What is equivalent to y=(x+3)2+53

viva [34]

The answer is y=2x+59

8 0

2 years ago

Read 2 more answers

Which equation is represented by the table

lyudmila [28]

Answer:

B. b = 3a + 2

Step-by-step explanation:

We can write the equation in slope-intercept form as b = ma + c, where,

m = slope/rate of change

c = y-intercept/initial value

✔️Find m using any two given pair of values, say (2, 8) and (4, 14):

Rate of change (m) = change in b/change in a

m = (14 - 8)/(4 - 2)

m = 6/2

m = 3

✔️Find c by substituting (a, b) = (2, 8) and m = 3 into b = ma + c. Thus:

8 = 3(2) + c

8 = 6 + c

8 - 6 = c

2 = c

c = 2

✔️Write the equation by substituting m = 3 and c = 2 into b = ma + c. Thus:

b = 3a + 2

4 0

2 years ago

Using the same standard number cube, describe an event that would be considered “as likely as not."

asambeis [7]

Answer:

Step-by-step explanation:

If u roumd u can blah blah blah, then u can blah blah blaah blahhh blah, last u carry the three. GIVE ME POINTS!!!!!

7 0

2 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

3 years ago