A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
1.323 as a percent is 132.3% because you take the decimal and move it two spaces to the right->
Answer:
1.-113
2.62
Step-by-step explanation:
1.-9^2+3(-9)-5
-81+-27-5
-113
2.5(7-(-9))+2(-9)
5*16-18
80-18
62
Answer:
Yes
Step-by-step explanation:
Graph this function on your calculator and you will see an upwards graph, if the range (y), -1 can be mapped on the graph, it is within the range.
