<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
2 x 2 x 7, or 2^2 x 7
Step-by-step explanation:
Let us use prime factorization to find the prime numbers that make up 28:
28 = 2 x 14
2 is a prime number, 14 is not, so we have our first prime, 2.
14 = 2 x 7
We then further break the number down into two prime numbers, 2 and 7. Since 2 and 7 are prime and we can't break them down any further our answer is 2 x 2 x 7, or 2^2 x 7.
Answer:
12
Step-by-step explanation:
