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gayaneshka [121]
3 years ago
15

PLEASE HELP!

Physics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

False. Exercise should be around or at least one hour per day.

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Could someone help me on #7?
ozzi

i would sat C then the impact is weaker

8 0
3 years ago
A 1 000-V battery, a 3 000-Ω resistor, and a 0.50-μF capacitor are connected in series with a switch. The time constant for such
vampirchik [111]

Answer:

The current in the circuit at a time interval of τ seconds after the switch has been closed is 0.123 A

Explanation:

The time constant for an R and C in series circuit is given by τ = RC.

R = 3000 ohms, C = 0.5 × 10⁻⁶ F = 5.0 × 10⁻⁷ F

τ = 3000 × 5 × 10⁻⁷ = 0.015 s

The voltage across a capacitor as it charges is given be

V(t) = Vs (1 - e⁻ᵏᵗ)

where k = 1/τ

At the point when t = τ, the expassion becomes

V(t = τ) = 1000 (1 - e⁻¹) = 0.632 × 1000 = 632 V

Current flows as a result of potential difference,.

Current in the circuit at this time t =  τ is given by

I = (Vs - Vc)/R

Vs = source voltage = 1000 V

Vc = Voltage across the capacitor = 632 V

R = 3000 ohms

I = (1000 - 632)/3000 = 0.123 A

6 0
4 years ago
Katie practiced the fuute for 45 minutes then she ate a snack for 15 minutes. next,she watched television for 30 minutes,until 6
Akimi4 [234]
Started at 4.30 p.m ,15+45+30=1 hr 30 mins,6.00-1 hr 30 mins=4.30 p.m
6 0
4 years ago
The quantity x to be determined from the equation X=P-Q.
Softa [21]

Answer:

the correct answer will be 6.82 %that is 7%

p(1.27)-q(0.83) =x=0.44

0.02+0.01 =0.03 (maximum uncertainty)

percentage uncertainty =0.03/0.44×100 %

=6.82%

=7%

Explanation: it was d on my end

5 0
2 years ago
What fundamental frequency would you expect from blowing across the top of an empty soda bottle that is 24 cm deep
kari74 [83]

Answer:

708.3 Hz

Explanation:

For an open-air column, like the empty can, the fundamental frequency is given by

f_1 = \frac{v}{2L}

where

v = 340 m/s is the speed of sound

L is the length of the column

In this problem, the length of the bottle is

L = 24 cm = 0.24 m

Therefore, the fundamental frequency is

f_1 = \frac{340 m/s}{2(0.24 m)}=708.3 Hz

8 0
3 years ago
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