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MissTica
3 years ago
9

Please help for brainliest.

Mathematics
2 answers:
kherson [118]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Neporo4naja [7]3 years ago
4 0
The answer is c 57.29 so the problem would be (y=0.05x750+19.79) 0.05x750=37.5 then 37.5+19.79=57.29 so y= 57.29
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PLEASE ANSWER QUICK A team is ordering sweatshirts and sweatpants for its players. Each sweatshirt costs ​$25 and each pair of s
tankabanditka [31]

Answer:

25x+ 21y

You multiply x by sweatshirts and y by sweatpants

Step-by-step explanation:

I don't know what sport your talking about or how many people are on the team so im not really sure but hete

7 0
3 years ago
Please simplify: w^2-w-12
Rasek [7]
1: w=3
2:w=-4
( 1): ''w2'' was replaced by ''w^2''
w^2+w-(12)=0
3 0
4 years ago
Read 2 more answers
Solve for x in a right triangle (show work)
AnnZ [28]

Answer:

35.09°

Step-by-step explanation:

You can use cos theta to find the value of x.

Let us solve now.

They have already given the lengths of the hypotenuse and adjacent.

Hypotenuse = 33

Adjacent = 27

Let us solve now.

Cos x = Adjacent ÷ Hypotenuse

Cos x = 27 ÷ 33

Cos x = 0.8181

x = Cos⁻¹ 0.8181

x = 35.09°

Hope this helps you :-)

Let me know if you have any other questions :)

5 0
2 years ago
Write a formula for the function g(x) obtained when the graph of f(x) = 1/x is shifted down 4 units and to the right 6 units .
charle [14.2K]

Answer:  g(x) = \frac{1}{x-6} - 4

This can be written out as g(x) = 1/(x-6) - 4

The "x-6" is in the denominator, while the "-4" is not.

=============================================================

Explanation:

We'll start with the parent function f(x) = \frac{1}{x}

When we shift 4 units down, we're subtracting 4 from the y coordinate of each point on the curve. Which is the same as subtracting 4 from f(x) because y = f(x).

So we have h(x) = f(x) - 4 = \frac{1}{x} - 4 as an intermediate step.

Then to shift 6 units to the right, we'll replace every x with "x-6". Imagine we kept the h(x) curve completely still, and instead we moved the xy axis 6 units to the left. This would give the illusion of h(x) moving 6 units to the right if we made the xy axis stay still. So that's why we go for "x-6" instead of "x+6".

Therefore, we end up with g(x) = \frac{1}{x-6} - 4

Side note: plugging in x = 6 leads to a division by zero error. This would mean x = 6 is not in the domain.

5 0
3 years ago
For vectors u= (3,4) and v= (1,3) find CompuV and the angle between u and v.
vampirchik [111]

Answer:

The angle between the given vectors u and v is \theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

Step-by-step explanation:

Given vectors are \overrightarrow{u}=(3,4) and \overrightarrow{v}=(1,3)

Now compute the dot product of u and v:

\overrightarrow{u}.\overrightarrow{v}=(3,4).(1,3)

  =(3)(1)+(4)(3)

  =3+12

 =15

Now find the magnitude of u and v:

|\overrightarrow{u}|=\sqrt{3^2+4^2}

=\sqrt{9+16}

=\sqrt{25}

=5

|\overrightarrow{u}|=5

|\overrightarrow{v}|=\sqrt{1^2+3^2}

=\sqrt{1+9}

=\sqrt{10}

|\overrightarrow{v}|=\sqrt{10}

To find the angle between the given vectors

\overrightarrow{u}.\overrightarrow{v}=|\overrightarrow{u}|\overrightarrow{v}|cos\theta

\theta=cos^{-1}\left[\frac{\overrightarrow{u}.\overrightarrow{v}}{|\overrightarrow{u}|\overrightarrow{v}|}\right]

=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]

=cos^{-1}\left[\frac{15}{5\times \sqrt{10}}\right]

\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

Therefore the angle between the vectors u and v is

\theta=cos^{-1}\left[\frac{3}{\sqrt{10}}\right]

3 0
3 years ago
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